I know if i use grep -n that the output will have the lines numbered but is there a way to grep the actually line number.
so like this
grep -n "one" /usr/dict/numbers
1:one
21:twenty-one
31:thirty-one
41:forty-one
51:fifty-one
61:sixty-one
71:seventy-one
81:eighty-one
91:ninety-one
... (1 Reply)
Hi Folks,
I am searching for a pattern in logs through putty by opening the file in vi editor
and reaching to the last of the file by $ and then searching the pattern , lets say I have to search the pattern abc then it would be ?abc Now I want line numbers along with the matching pattern to be... (3 Replies)
Hi,
I have got the below requirement. please suggest.
I have a file like,
Processing Item is:
/data/ing/cfg2/abc.txt
/data/ing/cfg3/bgc.txt
Processing Item is:
/data/cmd/for2/ght.txt
/data/kernal/config.klgt.txt
I want to process the above file to get the output file like,
... (5 Replies)
I'm trying to grep lines where the digits at the end of each line are greater than digits. Tried this but it will only allow me to specify 2 digits. Any ideas would greatly be appreciated. grep -i '\<\{3,4,5\}\>' file
---------- Post updated at 05:58 PM ---------- Previous update was at 05:41... (1 Reply)
here is what i want to achieve.. i have a file with below contents
cat fileName
blah blah blah
.
.DROP this
REJECT that
.
--sport 7800 -j REJECT --reject-with icmp-port-unreachable
--dport 7800 -j REJECT --reject-with icmp-port-unreachable
.
.
.
more blah blah blah
--dport 3306... (14 Replies)
Hai,
I want to select only line numbers into a file if some pattern matches. I have written my script like below but its not working.
#!/bin/sh
file='/home/testfile1'
filesearch='/home/test00'
while read line
do
search=`echo $line |cut -c 1-24`
echo $search
echo `grep -n ""... (3 Replies)
We are using Red Hat Linux.
I have a flat file with among other things, the following lines, which appear occasionally throughout the file:
Using sed, I delete this line:
L;L;L;L;R;R;R;L;R;L;R;R;R;L;L;L
With:
/^;;;;;*/d
Works fine every time.
However, I cannot delete... (6 Replies)
Hi ,
I have a file where i have modifed certain things compared to original file . The difference of the original file and modified file is as follows.
# diff mir_lex.c.modified mir_lex.c.orig
3209c3209
< if(yy_current_buffer -> yy_is_our_buffer == 0) {
---
>... (5 Replies)
How would you grep for a line containing only 5 numbers? Something like this.
10 2 12 1 13 (4 Replies)
Discussion started by: cokedude
4 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)