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Top Forums Shell Programming and Scripting Find file size difference in two files using awk Post 302498375 by bartus11 on Monday 21st of February 2011 07:15:20 AM
Old 02-21-2011
Try:
Code:
awk 'NR==FNR{a[$2]=$1}NR!=FNR{a[$2]-=$1}END{for (i in a){if (a[i]!=0){print (a[i]<0)?-a[i]:a[i],i}}}' f1 f2

 

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ppmquantall(1)						      General Commands Manual						    ppmquantall(1)

NAME
ppmquantall - run ppmquant on a bunch of files all at once, so they share a common colormap SYNOPSIS
ppmquantall [-ext extension] ncolors ppmfile ... DESCRIPTION
Takes a bunch of portable pixmap as input. Chooses ncolors colors to best represent all of the images, maps the existing colors to the new ones, and overwrites the input files with the new quantized versions. If you don't want to overwrite your input files, use the -ext option. The output files are then named the same as the input files, plus a period and the extension text you specify. Verbose explanation: Let's say you've got a dozen pixmaps that you want to display on the screen all at the same time. Your screen can only display 256 different colors, but the pixmaps have a total of a thousand or so different colors. For a single pixmap you solve this problem with ppmquant; this script solves it for multiple pixmaps. All it does is concatenate them together into one big pixmap, run ppmquant on that, and then split it up into little pixmaps again. (Note that another way to solve this problem is to pre-select a set of colors and then use ppmquant's -map option to separately quantize each pixmap to that set.) SEE ALSO
ppmquant(1), ppm(5) AUTHOR
Copyright (C) 1991 by Jef Poskanzer. 27 July 1990 ppmquantall(1)
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