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Top Forums Shell Programming and Scripting Cannot compare argument in if statement in csh/grep command if argument starts with “-“ Post 302498275 by sarbjit on Monday 21st of February 2011 12:23:17 AM
Old 02-21-2011
Finally i found the soln to my problem.

For prob1, i need to use code like
Code:
If ("$argv[1]" == “-debug”) then
  Echo “in loop”
  Endif

i.e. $argv[1] should be enclosed in double quotes.

For problem while using grep command, is to use it like
Code:
grep '\-debug' filename

 

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ZGREP(1)						      General Commands Manual							  ZGREP(1)

NAME
zgrep - search possibly compressed files for a regular expression SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename... DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code: (-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep. If the GREP environment variable is set, zgrep uses it as the grep program to be invoked. EXIT CODE
2 - An option that is not supported was specified. AUTHOR
Charles Levert (charles@comm.polymtl.ca) SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1) ZGREP(1)
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