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Full Discussion: problem with if condition
Top Forums Shell Programming and Scripting problem with if condition Post 302498235 by Scott on Sunday 20th of February 2011 05:51:53 PM
Old 02-20-2011
Code:
if [ "$i" = "END"]

Seems you're missing a space before ]

Code:
if [ "$i" = "END" ]

This User Gave Thanks to Scott For This Post:
 

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DO(7)							  PostgreSQL 9.2.7 Documentation						     DO(7)

NAME
DO - execute an anonymous code block SYNOPSIS
DO [ LANGUAGE lang_name ] code DESCRIPTION
DO executes an anonymous code block, or in other words a transient anonymous function in a procedural language. The code block is treated as though it were the body of a function with no parameters, returning void. It is parsed and executed a single time. The optional LANGUAGE clause can be written either before or after the code block. PARAMETERS
code The procedural language code to be executed. This must be specified as a string literal, just as in CREATE FUNCTION. Use of a dollar-quoted literal is recommended. lang_name The name of the procedural language the code is written in. If omitted, the default is plpgsql. NOTES
The procedural language to be used must already have been installed into the current database by means of CREATE LANGUAGE. plpgsql is installed by default, but other languages are not. The user must have USAGE privilege for the procedural language, or must be a superuser if the language is untrusted. This is the same privilege requirement as for creating a function in the language. EXAMPLES
Grant all privileges on all views in schema public to role webuser: DO $$DECLARE r record; BEGIN FOR r IN SELECT table_schema, table_name FROM information_schema.tables WHERE table_type = 'VIEW' AND table_schema = 'public' LOOP EXECUTE 'GRANT ALL ON ' || quote_ident(r.table_schema) || '.' || quote_ident(r.table_name) || ' TO webuser'; END LOOP; END$$; COMPATIBILITY
There is no DO statement in the SQL standard. SEE ALSO
CREATE LANGUAGE (CREATE_LANGUAGE(7)) PostgreSQL 9.2.7 2014-02-17 DO(7)
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