You're missing a space after [. And you should always quote input parameters and variables, especially if you don't know whether they are set / exist. Quoting literal strings / values is a question of preference.
Hi
I am doing a script like
if
then
echo "table name dosent exist"
exit
fi
the problem is if $table_name is null then i am getting the error
Please help me
Thanks in advance (2 Replies)
hi
i am trying to compare a value with value 50. but i am getting
"
I am using
if
then
echo "------------"
fi
please help
thanks in advance
Satya (2 Replies)
Im trying to fix my /etc/weekly that rotates various logs however it does them no matter what filesize they are and i want them to only do it if there file size exceeds 2M or something. So I'm playing with a script to get the filesize using a ls -l command which works and puts the value into a... (3 Replies)
Hello all, :confused:
I am not getting this error.
Pls help me.
./construct_operon.sh: line 5:
#!/bin/bash
# Construct Operons using gene pairs.
rm -rf operons_result
lines=`awk 'END {print NR}' ecoli_operons`
while ;
do
head -1 ecoli_operons | awk '{print $1"\n"$2}' > pattern
... (5 Replies)
find . -name "*.*"|xargs grep WT:DBF_WL>> $F
Wfexist=`cat $F|grep $i`
echo $Wfexist
if ;
then
echo $Wfexist
echo "Workflow Exist"
else
touch $O
chmod 777 $O
echo $Wfexist
echo $WfExist >> $O
fi
I am getting the error that -ne: unary operator expected in the line with red... (2 Replies)
I get the following error
./get_NE05: line 42:
while
do
echo ${STRING_NAME}
J=1
if ; then
EXT=0$I
else
EXT=$I
fi
while
do
echo $I-$J
#calculating last occurrence
OCCURRENCE=`grep -io "${STRING_NAME}"... (3 Replies)
i=0
while
Shell script reports an error "unary operator expected" pointing the above line.
$i by default is 0 and holds integer value and $buf is also holding integer value.
Please can some one let me know what is missing.
Thanks. (1 Reply)
Hi
I have problem with my script.
I dont now why but i don't change anything and script stop working.
this is my code:
#!/bin/sh
for i in `ps -A | grep pocron.sh | grep -v grep | awk '{print $2}'`
do
COUNT=$((COUNT+1))
done
ostatnie_wykonanie=`cat porader.log`... (1 Reply)
In all my Googling, this usually happens when someone is comparing a variable, and that variable is unset. That doesn't appear to be the case for me...
#!/bin/bash -x
while read line
do
f=$(echo $line | tr -s ' ' | cut -d' ' -f 3)
echo $f
if
then
echo "This... (2 Replies)
Discussion started by: jnojr
2 Replies
LEARN ABOUT SUSE
alter_operator
ALTER OPERATOR(7) SQL Commands ALTER OPERATOR(7)NAME
ALTER OPERATOR - change the definition of an operator
SYNOPSIS
ALTER OPERATOR name ( { lefttype | NONE } , { righttype | NONE } ) OWNER TO newowner
DESCRIPTION
ALTER OPERATOR changes the definition of an operator. The only currently available functionality is to change the owner of the operator.
You must own the operator to use ALTER OPERATOR. To alter the owner, you must also be a direct or indirect member of the new owning role,
and that role must have CREATE privilege on the operator's schema. (These restrictions enforce that altering the owner doesn't do anything
you couldn't do by dropping and recreating the operator. However, a superuser can alter ownership of any operator anyway.)
PARAMETERS
name The name (optionally schema-qualified) of an existing operator.
lefttype
The data type of the operator's left operand; write NONE if the operator has no left operand.
righttype
The data type of the operator's right operand; write NONE if the operator has no right operand.
newowner
The new owner of the operator.
EXAMPLES
Change the owner of a custom operator a @@ b for type text:
ALTER OPERATOR @@ (text, text) OWNER TO joe;
COMPATIBILITY
There is no ALTER OPERATOR statement in the SQL standard.
SEE ALSO
CREATE OPERATOR [create_operator(7)], DROP OPERATOR [drop_operator(7)]
SQL - Language Statements 2010-05-14 ALTER OPERATOR(7)