Here is a C program I got back in 2004. You should be able to compile it on any UNIX system with the standard C compiler. You run it and provide your number of seconds since EPOCH value and it will print out the date and time. You could modify the print statement or use some other shell mechanism to change the output to what you are looking for.
Enjoy,
-Dave
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Last edited by vgersh99; 02-17-2011 at 12:56 PM..
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This User Gave Thanks to DaveJohnson For This Post:
Solaris 10 doesn't seem to like me a lot. I am trying to run a simple script to accept date and return epoch of that date:
#!/usr/bin/perl -w
use strict;
use Time::ParseDate;
my($date1)="Mon Mar 27 05:54:08 CDT 2009";
chomp $date1;
#Convert to seconds since start of epoch
my $time1 =... (3 Replies)
Hi all!
I have a "simple" problem:
I want to convert a date and time string (YYYYMMDDhhmmss) to epoch (unix time) in a shellscript.
I want to use the "date/time" string as an input to the script, eg:
scriptname.sh 20090918231000 and get the epoch format echoed out.
Is there an... (3 Replies)
System: HP-UX
Kornshell
Perl is installed, but not POSIX
Hello,
I am calculating a future date/time. To do this I take the system date in epoch format and add to it. I now need to take the new epoch date and convert it to MMDDYYHHmm format.
Any help with this is greatly appreciated. (4 Replies)
Hi,
I need to take the unix time and format it to a date/time string like this
yyyymmdd,hhmmss
I'm wrting in shell but have tried calling perl, but all the perl options I found on here puts output to Thu Jan 1 00:00:00 1970 format.
Any help?
Cheers
Neil (4 Replies)
Hi all ,
I need to know how to convert a time stamp entered by the user to be converted to GMT/UTC(epoch time) using mktime() and gmtime()
for exapample the input will be put in the form
ptm.tm_sec = 0;
ptm.tm_min = 59;
ptm.tm_hour = 11;
ptm.tm_mday = 20;... (2 Replies)
Hi all,
In terminal when I enter:
date -j -f date -j -f "%Y/%m/%d %T" "2011/09/30 13:00:00" +"%s"
The output is:
When I put 2011/09/30 in var A, and I subsequently enter:
date -j -f date -j -f "%Y/%m/%d %T" "${A} 13:00:00" +"%s"
The output is: (10 Replies)
i can probably script this in bash, but, i was wondering, does anyone know of a simple way to translate a given time to epoch?
date -d@"29/Oct/2013:17:53:11"
the user would specify the date: 29/Oct/2013:17:53:11
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so i have to perform a certain task at set times. for instance, i need to run a job at 12:30am every night, and other jobs, i only need to have them run on saturdays.
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im looking for a... (3 Replies)
I am not able to pass date stored in a variable as an argument to date command. I get current date value for from_date and to_date
#!/usr/bin/ksh
set -x
for s in server ; do
ssh -T $s <<-EOF
from_date="12-Jan-2015 12:02:09"
to_date="24-Jan-2015 13:02:09"
echo \$from_date
echo... (7 Replies)