I still need an unprocessed sample of your last output.
As in:
obscure the usernames and Ip addresses and whatever but I need to see what it really looks like. Without that I can't whip up anything I know will work. I can't even tell why you're grepping for 'console' at this point (my 'last' output never contains it).
the method to find out the all the user who are the current user of the system?
i tried with the who. but with that i receive the TTY like something. (3 Replies)
Hi
I am using mailx to send email and am wondering if there is a way I can send the email from a different user than the user logged in.
something like do-not-reply@xyz.com
Thank you. (1 Reply)
Hello,
i know who command gives you the time when particular user logged in. And subtracting today's date and time from the one found in who we can get how much time user logged in. But this can get very much clumsy as we can't subtract date directly in unix . Is there any other way or command... (4 Replies)
How do I confirm if a user logged in, is remote or local? In the case if the user is remote, how to be sure what authentication/method is it using, like LDAP, NIS or other? (2 Replies)
Hey guys
I need a script that reads a login name and verifies if that user is currently logged in
i have found few commands like "who" and "users"
but i wonder how can i verify it that login name is logged in or not? (3 Replies)
hi!
How can I find into:
/var/log/messages.4
/var/log/messages.3
/var/log/messages.2
/var/log/messages.1
/var/log/messages
The last user do a login? (for example user1)
My idea is to search by the pattern "Accepted password for" buy I necessary search into all files first and in the... (2 Replies)
Hi All,
We use putty to connect to a unix box. We want to identify the folks involved in running certain shell scripts on the server.
I want to identify the windows user id of those folks who have logged through Putty to run the scripts.As unix-id is shared by more than two folks, tracking... (3 Replies)
Discussion started by: mdkareemuddin
3 Replies
LEARN ABOUT DEBIAN
bashbug
BASHBUG(1) bashbug BASHBUG(1)NAME
bashbug - report a bug in bash
SYNOPSIS
bashbug [--help] [--version] [bug-report-email-addresses]
DESCRIPTION
bashbug is a utility for reporting bugs in Bash to the maintainers.
bashbug will start up your preferred editor with a preformatted bug report template for you to fill in. Save the file and quit the editor
once you have completed the missing fields. bashbug will notify you of any problems with the report and ask for confirmation before
sending it. By default the bug report is mailed to both the GNU developers and the Debian Bash maintainers. The recipients can be changed
by giving a comma separated list of bug-report-email-addresses.
If you invoke bashbug by accident, just quit your editor. You will always be asked for confirmation before a bug report is sent.
OPTIONS --help
Show a brief usage message and exit.
--version
Show the version of bashbug and exit.
bug-report-email-addresses
Comma separated list of recipients' email addresses. By default the report is mailed to both the GNU developers and the Debian Bash
maintainers.
ENVIRONMENT
DEFEDITOR
Editor to use for editing the bug report.
EDITOR
Editor to use for editing the bug report (overridden by DEFEDITOR).
SEE ALSO bash(1), reportbug(1), update-alternatives(8) for preferred editor.
AUTHOR
This manual page was written by Christer Andersson <klamm@comhem.se> for the Debian project (but may be used by others).
GNU Bash 3.1 11 December 2007 BASHBUG(1)