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Full Discussion: TEST Command
Top Forums Shell Programming and Scripting TEST Command Post 302497478 by Aswex on Thursday 17th of February 2011 10:27:12 AM
Old 02-17-2011
TEST Command

Hello,

I need help with a test command.

Here is what I am trying to do :

I've got an interactive script that check if configuration files exist on 2 different directories, then all configuration files are print on screen by a short name.

My problem is when you type a "wrong name" or "enter" instead of one the short name given.

How can I get create a test that will check to see if you have exactly choosen one of the configuration files given ?

Code:
lst_proto=$(cat ${rep_config}/*.cfg | grep "#name_transfert#" | cut -d " " -f"2" | sort)
        echo "${lst_proto} "

                lst_proto_old=$(cat ${rep_config}/_HISTO_FIC_CFG/*.cfg | grep "#name_transfert#" | cut -d " " -f"2" | sort)
                if [ -z ${nb_proto_old} ];
        then
                echo " "
                echo "--------OLD PROTOTYPE-------------"
                echo " "
                echo "${lst_proto_old} "
                echo " "
        fi

        echo "Please choose your configuration file : \c"

        read prototype

        echo "-------------------------------------------"
        echo "You have choosen : ${prototype} \n"
        echo "-------------------------------------------"
        echo " "
#------------------------complet name files------------------
        cd ${rep_config}
        nom_cfg=$(${prototype}.cfg)

                if [ "#"${nom_cfg}"#" == "##" ];
                then
#------------------------OLD complet name files----------------------------
                        rep_config="${rep_config}/_HISTO_FIC_CFG"
                        cd ${rep_config}
                        nom_cfg=$(${prototype}.cfg)
                fi

I don't even know if it's possible.

Thanls for your help
 

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ECHO(3) 								 1								   ECHO(3)

echo - Output one or more strings

SYNOPSIS
void echo (string $arg1, [string $...]) DESCRIPTION
Outputs all parameters. echo is not actually a function (it is a language construct), so you are not required to use parentheses with it. echo (unlike some other language constructs) does not behave like a function, so it cannot always be used in the context of a function. Additionally, if you want to pass more than one parameter to echo, the parameters must not be enclosed within parentheses. echo also has a shortcut syntax, where you can immediately follow the opening tag with an equals sign. Prior to PHP 5.4.0, this short syn- tax only works with the short_open_tag configuration setting enabled. I have <?=$foo?> foo. PARAMETERS
o $arg1 - The parameter to output. o $... - RETURN VALUES
No value is returned. EXAMPLES
Example #1 echo examples <?php echo "Hello World"; echo "This spans multiple lines. The newlines will be output as well"; echo "This spans multiple lines. The newlines will be output as well."; echo "Escaping characters is done "Like this"."; // You can use variables inside of an echo statement $foo = "foobar"; $bar = "barbaz"; echo "foo is $foo"; // foo is foobar // You can also use arrays $baz = array("value" => "foo"); echo "this is {$baz['value']} !"; // this is foo ! // Using single quotes will print the variable name, not the value echo 'foo is $foo'; // foo is $foo // If you are not using any other characters, you can just echo variables echo $foo; // foobar echo $foo,$bar; // foobarbarbaz // Some people prefer passing multiple parameters to echo over concatenation. echo 'This ', 'string ', 'was ', 'made ', 'with multiple parameters.', chr(10); echo 'This ' . 'string ' . 'was ' . 'made ' . 'with concatenation.' . " "; echo <<<END This uses the "here document" syntax to output multiple lines with $variable interpolation. Note that the here document terminator must appear on a line with just a semicolon. no extra whitespace! END; // Because echo does not behave like a function, the following code is invalid. ($some_var) ? echo 'true' : echo 'false'; // However, the following examples will work: ($some_var) ? print 'true' : print 'false'; // print is also a construct, but // it behaves like a function, so // it may be used in this context. echo $some_var ? 'true': 'false'; // changing the statement around ?> NOTES
Note Because this is a language construct and not a function, it cannot be called using variable functions. SEE ALSO
print(3), printf(3), flush(3), Heredoc syntax. PHP Documentation Group ECHO(3)
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