Sponsored Content
Top Forums Shell Programming and Scripting Awk to Search and Replace inside the pipe "|" Post 302497388 by fspalero on Thursday 17th of February 2011 04:43:58 AM
Old 02-17-2011
Quote:
Originally Posted by ctsgnb
Code:
sed 's/"//g;s:|:"|":g;s:.*:"&":' infile


hi ctsgnb, It worked like a charm. Thank you.
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

Explain the line "mn_code=`env|grep "..mn"|awk -F"=" '{print $2}'`"

Hi Friends, Can any of you explain me about the below line of code? mn_code=`env|grep "..mn"|awk -F"=" '{print $2}'` Im not able to understand, what exactly it is doing :confused: Any help would be useful for me. Lokesha (4 Replies)
Discussion started by: Lokesha
4 Replies

2. Shell Programming and Scripting

Sed , Replace a "variable text" inside of a statement

Please Help... I am trying to manipulte the following line Before : <user:Account_Password>002786</user:Account_Password> the password is the "variable", i need to delete / omit the password in the file, (it occurs several thousand times) so the tag line looks like After:... (4 Replies)
Discussion started by: jackn7
4 Replies

3. Shell Programming and Scripting

awk's getline < "-" seems not work for pipe

Hi all, I have an gawk script to get user's input, So I use getline name < "-" (or getline name < "/dev/stdin") in my script They both work fine when my script deals with files. But it is broken for pipes. When I try "some command | my awk script", the variable name just gets an empty... (17 Replies)
Discussion started by: qiulang
17 Replies

4. Shell Programming and Scripting

cat $como_file | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g'

hi All, cat file_name | awk /^~/'{print $1","$2","$3","$4}' | sed -e 's/~//g' Can this be done by using sed or awk alone (4 Replies)
Discussion started by: harshakusam
4 Replies

5. Shell Programming and Scripting

Interesting question - Search and replace the word after sign "="

Hi Guys, Req your help in searching and replacing the word that comes after equals(=) symbol I would like to replace the sting in bold with a string in variable. d=ABCDF8C44C22 # grep -i NIM_MASTERID ${_NIMINFO} export NIM_MASTERID=00CDF8C44C00 I'm looking to replace any word that... (4 Replies)
Discussion started by: ajilesh
4 Replies

6. UNIX for Dummies Questions & Answers

sed for "/7.*" search and replace

Hi , I have this file having thousands of records in it . I want to remove every 9 digit number starting with 7 in it . The few lines from the sample file are "/-GEO-Prizm-Dashes-Covers-Caps-Trim/720000100-200742232-600022761.car"... (8 Replies)
Discussion started by: capri_drm
8 Replies

7. Shell Programming and Scripting

Script to search a string which is in between "" and replace it with another character

Hi, I am trying to search a string from a text file which is in between "" (Double Quotes) (Eg: "Unix"), and replace it with a | where ever it is appearing in the text file and save the file. Please help me. -kkmdv (6 Replies)
Discussion started by: kkmdv
6 Replies

8. Shell Programming and Scripting

awk command to replace ";" with "|" and ""|" at diferent places in line of file

Hi, I have line in input file as below: 3G_CENTRAL;INDONESIA_(M)_TELKOMSEL;SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL My expected output for line in the file must be : "1-Radon1-cMOC_deg"|"LDIndex"|"3G_CENTRAL|INDONESIA_(M)_TELKOMSEL"|LAST|"SPECIAL_WORLD_GRP_7_FA_2_TELKOMSEL" Can someone... (7 Replies)
Discussion started by: shis100
7 Replies

9. Shell Programming and Scripting

how to use "cut" or "awk" or "sed" to remove a string

logs: "/home/abc/public_html/index.php" "/home/abc/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" "/home/xyz/public_html/index.php" how to use "cut" or "awk" or "sed" to get the following result: abc abc xyz xyz xyz (8 Replies)
Discussion started by: timmywong
8 Replies

10. Shell Programming and Scripting

grep with "[" and "]" and "dot" within the search string

Hello. Following recommendations for one of my threads, this is working perfectly : #!/bin/bash CNT=$( grep -c -e "some text 1" -e "some text 2" -e "some text 3" "/tmp/log_file.txt" ) Now I need a grep success for some thing like : #!/bin/bash CNT=$( grep -c -e "some text_1... (4 Replies)
Discussion started by: jcdole
4 Replies
SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
All times are GMT -4. The time now is 09:16 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy