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Top Forums Shell Programming and Scripting [Awk] Extract block of with a particular pattern Post 302496643 by Chubler_XL on Monday 14th of February 2011 07:31:07 PM
Old 02-14-2011
Great solution rdcwayx,

Just a couple of slight tweaks to stop false positives (Bug Fix must start 3rd line) and also support number without proceeding letters (think that is what ##### was supposed to represent):

Code:
awk '
BEGIN{RS="==*\n";FS="--*\n"}
{for (i=1;i<=NF;i++) {if ($i~/[^\n]*\n[^\n]*\n(Bug |Fix |)[0-9]/||$i~/^RCS file:/) print $i OFS}}
' OFS="----------------------------"  infile

This User Gave Thanks to Chubler_XL For This Post:
 

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