Sponsored Content
Top Forums Shell Programming and Scripting If statement is not working in KSH Post 302495092 by fpmurphy on Wednesday 9th of February 2011 09:47:44 AM
Old 02-09-2011
It is also better practice to use:
Quote:
if [[...]]
instead of:
Quote:
if [...]
 

10 More Discussions You Might Find Interesting

1. UNIX for Dummies Questions & Answers

if statement in ksh

what is the problem with this comparison in ksh script: if " ] it gives syntx error (3 Replies)
Discussion started by: gfhgfnhhn
3 Replies

2. UNIX for Dummies Questions & Answers

Let statement in ksh HELP

I have: datafile contains 1234567890 >wc -c datafile | awk '{print $1}' >11 The program #!/bin/ksh let n = (wc -c datafile | awk '{print $1}') echo $n I expect n to be 11 but it gives error message. What is wrong with this statement? Thanks! (3 Replies)
Discussion started by: bobo
3 Replies

3. Shell Programming and Scripting

If statement not working

I understand this question probably poses some child like stupidity, but I can't get this if statement to work for love or money. #!/bin/ksh echo "Input either 1 or 2" read Num if ; then echo "Message 1" if ; then echo "Message 2" else echo "false" fi $ ksh decisions Input either 1... (6 Replies)
Discussion started by: Hazmeister
6 Replies

4. Shell Programming and Scripting

how to use if statement in ksh script

Hi, I need to compare two variables using if condition and i am not sure if am right or wrong. My code is like : if then echo "new file" else echo "old file and remove it" fi where both variables contain time : filetime contains the time when a file... (2 Replies)
Discussion started by: manmeet
2 Replies

5. Shell Programming and Scripting

ksh case statement

I am trying to write a ksh script using the case statement to select certain directories to remove. The directories that I am looking for are in the following format 2008-10-10. I want to exclude all other files/directories that contain anything other the 4 digit year,a dash, 2 digit month, a... (2 Replies)
Discussion started by: dgilc
2 Replies

6. UNIX for Dummies Questions & Answers

until statement not working

im trying to write an until statement which dont go onto the next stage until the user inputs a certain phrase. It is then stored in an array. Ive come up with this code so far but its not working and i dont know why. read in1 until do echo "Incorrect, try again" ... (2 Replies)
Discussion started by: strasner
2 Replies

7. Shell Programming and Scripting

KSH if statement

Hi guys, im new to UNIX so bear with me. would it be possible for me to create an if statement where i can have a key being entered and something happening after that. (bad explanation) eg. If user enters letter 'q' then close window or exit puTTy Thanks in advance (1 Reply)
Discussion started by: robbrad
1 Replies

8. Shell Programming and Scripting

If statement is not working.

Hi. With the help of this group I have created a shell script to find the factorial of a number. OK. Then I got wild.;) I tried to put in a check to make sure the entry is a number. read num If )) then echo "This is not a valid number. Try again." fi while (( $var <= $num)) more... (5 Replies)
Discussion started by: Ccccc
5 Replies

9. Shell Programming and Scripting

KSH If statement.

How can I search get if to pinpoint 1 word in a line and have it do something for me? example: KEY1="<< Response ... Total of 2 >> Sun Jun 19 15:30:18 2011 Tx Power Level is 27.7 Bm ~ " if ]; then command; else error; fi Thats just a quick sample. I want my if statement to se the... (5 Replies)
Discussion started by: 82280zx
5 Replies

10. Shell Programming and Scripting

If Not Diff statement in ksh 88

Hi I tried the below code where it is working properly #!/bin/ksh set -x date1_data=abc.txt date2_data=bcd.txt if diff $date1_data $date2_data >/dev/null ; then echo "Equal" else echo "Not Equal" fi Then I tried like below where i want to use only if fi not else part ... (3 Replies)
Discussion started by: smile689
3 Replies
SHELL-QUOTE(1p) 					User Contributed Perl Documentation					   SHELL-QUOTE(1p)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.8.4 2005-05-03 SHELL-QUOTE(1p)
All times are GMT -4. The time now is 07:35 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy