02-03-2011
remove characters from string based on occurrence of a string
Hello Folks..
I need your help ..
here the example of my problem..i know its easy..i don't all the commands in unix to do this especiallly sed...here my string..
dwc2_dfg_ajja_dfhhj_vw_dec2_dfgh_dwq
desired output is..
dwc2_dfg_ajja_dfhhj
it's a simple task with tail command, but my string size varies..only constant thing is ocuurance of this string "_vw_"
I greatly appretiate your help..
Thanks
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TAIL(1) General Commands Manual TAIL(1)
NAME
tail - deliver the last part of a file
SYNOPSIS
tail [ +-number[lbc][rf] ] [ file ]
tail [ -fr ] [ -n nlines ] [ -c ncharacters ] [ file ]
DESCRIPTION
Tail copies the named file to the standard output beginning at a designated place. If no file is named, the standard input is copied.
Copying begins at position +number measured from the beginning, or -number from the end of the input. Number is counted in lines, 1K
blocks or characters, according to the appended flag or Default is -10l (ten ell).
The further flag causes tail to print lines from the end of the file in reverse order; (follow) causes tail, after printing to the end, to
keep watch and print further data as it appears.
The second syntax is that promulgated by POSIX, where the numbers rather than the options are signed.
EXAMPLES
tail file
Print the last 10 lines of a file.
tail +0f file
Print a file, and continue to watch data accumulate as it grows.
sed 10q file
Print the first 10 lines of a file.
SOURCE
/sys/src/cmd/tail.c
BUGS
Tails relative to the end of the file are treasured up in a buffer, and thus are limited in length.
According to custom, option +number counts lines from 1, and counts blocks and characters from 0.
TAIL(1)