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UNIX for Dummies Questions & Answers
function parameter issue
Post 302493271 by zaxxon on Wednesday 2nd of February 2011 09:15:35 AM
02-02-2011
- Not escaping the | when handing it over as parameter of your function will not work, as it is a special symbol in the shell to pipe output from stdout to stdin of the next command. You should try escaping it or putting double quotes around it. You did escape the $ of $1 so why not do the same with the pipe?!
- $position is a variable not known/defined in awk. You might want to use something like awk -v position=$position ... to pass it to awk.
After correcting those, try again and let's see if it get's stuck again.
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LEARN ABOUT REDHAT
igawk
IGAWK(1) Utility Commands IGAWK(1) NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)