I have a script that is reading an existing report, pulling out the customer code, then tacking on the customer name from another file and replacing the existing customer code with the new field. This was written for me by someone else. I'm not real familiar with sed.
The data is getting into... (3 Replies)
Greetings,
I am doing something that I don't know if it is possible...
I have a file with a line looks like this:
<%s \n%s / %s \n%s \n>
and I am trying to replace this line with
<%s \n%s \n%s / %s \n%s \n>
in Shell script with sed command...
StringToReplace='%s \n%s / %s \n%s \n'... (2 Replies)
Hi,
I am beginner to Shell Scripting.
I have a String like this "testabcdef", i need the first character as it is and the remaining character should be replaced by the the '*' character. e.g(t***********)
PLZ Suggest me. (5 Replies)
I would like to replace /n with ',' and after replace remove last semicolon then put a open brace in starting and closing brace in end of line. See below example:
input:
1234
3455
24334
234
output:
('1234,'3455',24334','234')
Thanks (3 Replies)
How can I replace the follong text including to number 7000?
cat tmp0.txt
Winston (UK) Wong
I would the 7000 to replace Winston (UK) Wong.
I fail with method below:
sed ' s /Winston\(UK\)Wong/7000 tmp0.txt' (1 Reply)
Hi,
First find the special character, from the special character take next two bytes convert the bytes to decimal and replace with next present byte of decimal value times.
E.g.
Input: 302619ú1A?
Output: 302619(3 spaces for ú1A)??????????????????????????
Thanks,
Dines (27 Replies)
Hi,
I have a string wherein i need to replace special characters with backslash and that character.
Ex:
If my string is a=qwerty123@!,
then the new string should be a_new=qwerty123\@\!\,
Thanks (3 Replies)
Hi All,
I have a text file that contains
I1SP2 *=*=Y=M=D001D
My requirement is to replace all occurrence of =* to =Z
expected o/p is I1SP2 *=Z=Y=M=D001D
I have tried with
sed 's/=*/=Z/g' file
sed 's!\=*!\=Z/g' file
sed 's!\=*!\=Z!g' file
sed 's!\=\*!\=Z!g' file
but its not... (3 Replies)
Discussion started by: gotamp
3 Replies
LEARN ABOUT DEBIAN
sendemail
SendEmail(1) User Commands SendEmail(1)NAME
SendEmail - Lightweight, command line SMTP email client
SYNOPSIS
SendEmail -f ADDRESS [options]
OPTIONS -f ADDRESS
from (sender) email address
* At least one recipient required via -t, -cc, or -bcc * Message body required via -m, STDIN, or -o message-file=FILE
Common:
-t ADDRESS [ADDR ...]
to email address(es)
-u SUBJECT
message subject
-m MESSAGE
message body
-s SERVER[:PORT]
smtp mail relay, default is localhost:25
Optional:
-a FILE [FILE ...] file attachment(s)
-cc ADDRESS [ADDR ...] cc email address(es)
-bcc ADDRESS [ADDR ...]
bcc email address(es)
[32;1mParanormal:[m
-xu USERNAME
authentication user (for SMTP authentication)
-xp PASSWORD
authentication password (for SMTP authentication)
-l LOGFILE log to the specified file
-v verbosity, use multiple times for greater effect
-q be quiet (no stdout output)
-o NAME=VALUE
see extended help topic "misc" for details
Help:
--help TOPIC
The following extended help topics are available:
addressing
explain addressing and related options
message
explain message body input and related options
misc explain -xu, -xp, and others
networking
explain -s, etc
output explain logging and other output options
REPORTING BUGS
Report bugs to <http://bugs.debian.org/sendemail>
AUTHOR
sendemail was written by Brandon Zehm <caspian@dotconf.net> .
This manual page was written by Brandon Zehm and improved by Alejandro Garrido Mota <garridomota@gmail.com>, for the Debian project (and
may be used by others).
sendEmail September 2010 SendEmail(1)
01-19-2011
sed special character replace
