Sponsored Content
Top Forums Shell Programming and Scripting set variable using 'ls' with an 'or' conditional statement Post 302488920 by goodbenito on Tuesday 18th of January 2011 08:46:37 PM
Old 01-18-2011
set variable using 'ls' with an 'or' conditional statement

Hi,

I would like to set a variable using ls, but I need to be able to list two possibilities simultaneously, i.e., I'd like to do this all on one line. These are the two possible directories, but keep in mind only *one* will be present at any given time:

drwxrwxrwx 4 qtv qtv 16384 Nov 9 15:26 t2_tirm_tra_dark_fluid_5mm
drwxrwxrwx 4 qtv qtv 16384 Nov 9 15:26 FLAIRmosaic

So the code needs to be able to list one or the other at any given time and not error out when it sees that the other does not exist. This is what I've tried so far:

Code:
dir=`ls -d ./*FLAIR* ./*dark*`

This command errors out when the top dir doesn't contain one of the two directories. Any suggestions would be greatly appreciated. Thanks!
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

quoting in conditional statement

can somebody help, what quote i should use in below statement or what wrong of it ? the 1st (*) is a char, the 2nd and 3rd (*) is a wildcard if ] && ] && ] ................^ .............^ then echo "ok" fi thanks in advance. (2 Replies)
Discussion started by: 3Gmobile
2 Replies

2. Shell Programming and Scripting

conditional statement

Hi Does Unix have a conditional statement like Java as follows: Condition ? Statement1 : Statement2 Thanks (8 Replies)
Discussion started by: lalelle
8 Replies

3. Shell Programming and Scripting

conditional statement

Hi all, The following code is to find if a list of numbers from one file are within the range in another file. awk -F, '\ BEGIN { while ((getline < "file2") > 0) file2=$3 } {for (col1 in file2) if ($0>=30 && $1<=45) print $0} ' FILE1 But where I have the number 30 and 45, I... (3 Replies)
Discussion started by: dr_sabz
3 Replies

4. UNIX for Dummies Questions & Answers

Problem with conditional statement

Hi, I'm getting a "bad number" error from the following conditional if statement. I understand the results of the grep command are not being treated a an integer but am unsure of the correct syntax. Any help would be appreciated. if Thanks (2 Replies)
Discussion started by: dlafa
2 Replies

5. Shell Programming and Scripting

if conditional statement

Hi, I have a script like this: sample.sh mapping=$1 if then echo "program passed" fi I'm running the above script as ./sample.sh pass The script is not getting executed and says "integer expression expected" Could anyone kindly help me? (2 Replies)
Discussion started by: badrimohanty
2 Replies

6. UNIX for Dummies Questions & Answers

Conditional statement in bash

I want to combine 2 conditional statements by using -o in bash, but it won't work. if ; then echo "The number needs to be between 0 and $nr" fi Each time i execute the file it says: ./selectCitaat: line 10: syntax error near unexpected token `$1' (3 Replies)
Discussion started by: doc.arne
3 Replies

7. Shell Programming and Scripting

if statement with grep as conditional

Please see the script segment below for i in $files do echo $i if ; then case "$1" in "IE0263"|"IE0264"|"IE0267"|"IE0268") short_filename=`ls -l $i | cut -c108-136 | sort` ;; "IE0272"|"IE0273") short_filename=`ls -l $i | cut... (4 Replies)
Discussion started by: jmahal
4 Replies

8. Shell Programming and Scripting

Conditional Shell Statement

I want to add a conditional statement to a user's .profile file. I have a certain number of users that log in and use the rksh (Restricted Korn Shell). When they log in, it starts a certain program and when they exit this program, the system logs them out. When they are in this program, they can... (2 Replies)
Discussion started by: rjulich
2 Replies

9. UNIX for Advanced & Expert Users

conditional statement

I need to implement something like this. 1) search for a file(say *.doc) from a path (say /home/user/temp) 2) if file found & if file size > 0 : yes --> file valid else : print file not valid. I am trying to implement something like this, but seems i am terribly wrong somewhere.. ... (1 Reply)
Discussion started by: animesharma
1 Replies

10. Shell Programming and Scripting

conditional statement in awk

Hi all, I have a file containing the values that would be use as the basis for printing the lines of another set of files using awk. What I want to do is something like the one below: stdev.txt 0.21 0.42 0.32 0.25 0.15 file1.txt file2.txt file3.txt ..filen.txt 0.45 0.23 ... (4 Replies)
Discussion started by: ida1215
4 Replies
Template::Plugin::Directory(3pm)			User Contributed Perl Documentation			  Template::Plugin::Directory(3pm)

NAME
Template::Plugin::Directory - Plugin for generating directory listings SYNOPSIS
[% USE dir = Directory(dirpath) %] # files returns list of regular files [% FOREACH file = dir.files %] [% file.name %] [% file.path %] ... [% END %] # dirs returns list of sub-directories [% FOREACH subdir = dir.dirs %] [% subdir.name %] [% subdir.path %] ... [% END %] # list returns both interleaved in order [% FOREACH item = dir.list %] [% IF item.isdir %] Directory: [% item.name %] [% ELSE %] File: [% item.name %] [% END %] [% END %] # define a VIEW to display dirs/files [% VIEW myview %] [% BLOCK file %] File: [% item.name %] [% END %] [% BLOCK directory %] Directory: [% item.name %] [% item.content(myview) | indent -%] [% END %] [% END %] # display directory content using view [% myview.print(dir) %] DESCRIPTION
This Template Toolkit plugin provides a simple interface to directory listings. It is derived from the Template::Plugin::File module and uses Template::Plugin::File object instances to represent files within a directory. Sub-directories within a directory are represented by further "Template::Plugin::Directory" instances. The constructor expects a directory name as an argument. [% USE dir = Directory('/tmp') %] It then provides access to the files and sub-directories contained within the directory. # regular files (not directories) [% FOREACH file IN dir.files %] [% file.name %] [% END %] # directories only [% FOREACH file IN dir.dirs %] [% file.name %] [% END %] # files and/or directories [% FOREACH file IN dir.list %] [% file.name %] ([% file.isdir ? 'directory' : 'file' %]) [% END %] The plugin constructor will throw a "Directory" error if the specified path does not exist, is not a directory or fails to "stat()" (see Template::Plugin::File). Otherwise, it will scan the directory and create lists named '"files"' containing files, '"dirs"' containing directories and '"list"' containing both files and directories combined. The "nostat" option can be set to disable all file/directory checks and directory scanning. Each file in the directory will be represented by a Template::Plugin::File object instance, and each directory by another "Template::Plugin::Directory". If the "recurse" flag is set, then those directories will contain further nested entries, and so on. With the "recurse" flag unset, as it is by default, then each is just a place marker for the directory and does not contain any further content unless its "scan()" method is explicitly called. The "isdir" flag can be tested against files and/or directories, returning true if the item is a directory or false if it is a regular file. [% FOREACH file = dir.list %] [% IF file.isdir %] * Directory: [% file.name %] [% ELSE %] * File: [% file.name %] [% END %] [% END %] This example shows how you might walk down a directory tree, displaying content as you go. With the recurse flag disabled, as is the default, we need to explicitly call the "scan()" method on each directory, to force it to lookup files and further sub-directories contained within. [% USE dir = Directory(dirpath) %] * [% dir.path %] [% INCLUDE showdir %] [% BLOCK showdir -%] [% FOREACH file = dir.list -%] [% IF file.isdir -%] * [% file.name %] [% file.scan -%] [% INCLUDE showdir dir=file FILTER indent(4) -%] [% ELSE -%] - [% f.name %] [% END -%] [% END -%] [% END %] This example is adapted (with some re-formatting for clarity) from a test in t/directry.t which produces the following output: * test/dir - file1 - file2 * sub_one - bar - foo * sub_two - waz.html - wiz.html - xyzfile The "recurse" flag can be set (disabled by default) to cause the constructor to automatically recurse down into all sub-directories, creating a new "Template::Plugin::Directory" object for each one and filling it with any further content. In this case there is no need to explicitly call the "scan()" method. [% USE dir = Directory(dirpath, recurse=1) %] ... [% IF file.isdir -%] * [% file.name %] [% INCLUDE showdir dir=file FILTER indent(4) -%] [% ELSE -%] ... The directory plugin also provides support for views. A view can be defined as a "VIEW ... END" block and should contain "BLOCK" definitions for files ('"file"') and directories ('"directory"'). [% VIEW myview %] [% BLOCK file %] - [% item.name %] [% END %] [% BLOCK directory %] * [% item.name %] [% item.content(myview) FILTER indent %] [% END %] [% END %] The view "print()" method can then be called, passing the "Directory" object as an argument. [% USE dir = Directory(dirpath, recurse=1) %] [% myview.print(dir) %] When a directory is presented to a view, either as "[% myview.print(dir) %]" or "[% dir.present(view) %]", then the "directory" "BLOCK" within the "myview" "VIEW" is processed. The "item" variable will be set to alias the "Directory" object. [% BLOCK directory %] * [% item.name %] [% item.content(myview) FILTER indent %] [% END %] In this example, the directory name is first printed and the content(view) method is then called to present each item within the directory to the view. Further directories will be mapped to the "directory" block, and files will be mapped to the "file" block. With the recurse option disabled, as it is by default, the "directory" block should explicitly call a "scan()" on each directory. [% VIEW myview %] [% BLOCK file %] - [% item.name %] [% END %] [% BLOCK directory %] * [% item.name %] [% item.scan %] [% item.content(myview) FILTER indent %] [% END %] [% END %] [% USE dir = Directory(dirpath) %] [% myview.print(dir) %] AUTHORS
Michael Stevens wrote the original Directory plugin on which this is based. Andy Wardley split it into separate File and Directory plugins, added some extra code and documentation for "VIEW" support, and made a few other minor tweaks. COPYRIGHT
Copyright (C) 2000-2007 Michael Stevens, Andy Wardley. This module is free software; you can redistribute it and/or modify it under the same terms as Perl itself. SEE ALSO
Template::Plugin, Template::Plugin::File, Template::View perl v5.14.2 2011-12-20 Template::Plugin::Directory(3pm)
All times are GMT -4. The time now is 08:41 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy