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Full Discussion: Identify script please!
Top Forums Shell Programming and Scripting Identify script please! Post 302488582 by Chubler_XL on Monday 17th of January 2011 08:07:28 PM
Old 01-17-2011
Ok a couple of questions here firstly lets deal with filenames with spaces.

replace your for loops with:
Code:
find $DLDIR -name "*.zip"` | while read FILE ; do
 
 
find "$DLDIR" -name "*.zip"`| while read j ; do

Any references to $FILE or $j need quotes eg:
Code:
FILENAME=$(basename "$FILE")
UNPACKDIR=$(dirname "$FILE") 
 
rm "$j"

Now for permissions, if your find command supports -print0 you can fix ownership by doing this after the unzip:
Code:
find "$UNPACKDIR" -print0 | xargs -0 chmod 777

If not, you will need to do another while+read block and run chmod:
Code:
find "$UNPACKDIR" -print | while read CHFILE ; do
    chmod 777 "$CHFILE"
done

 

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expr(1) 						      General Commands Manual							   expr(1)

Name
       expr - evaluate expressions

Syntax
       expr arg...

Description
       The arguments are taken as an expression.  After evaluation, the result is written on the standard output.  Each token of the expression is
       a separate argument.

       The operators and keywords are listed below.  The list is in order of increasing precedence, with equal precedence operators grouped.

       expr | expr	   Yields the first expr if it is neither null nor 0.  Otherwise yields the second expr.

       expr & expr	   Yields the first expr if neither expr is null or 0.	Otherwise yields 0.

       expr relop expr	   The relop is one of < <= = != >= > and yields 1 if the indicated comparison is true, '0' if false.  The  comparison	is
			   numeric if both expr are integers, otherwise lexicographic.

       expr + expr
	    expr - expr
			   Yields addition or subtraction of the arguments.

       expr * expr
	    expr / expr
	    expr % expr
			   Yields multiplication, division, or remainder of the arguments.

       expr : expr	   The	matching  operator compares the string first argument with the regular expression second argument; regular expres-
			   sion syntax is the same as that of The (...) pattern symbols can be used to select a portion of the  first  argument.
			   Otherwise, the matching operator yields the number of characters matched ('0' on failure).

       ( expr ) 	   parentheses for grouping.

Examples
       The first example adds 1 to the Shell variable a:
       a=`expr $a + 1`
       The second example finds the file name part (least significant part) of the pathname stored in variable a,
       expr $a : '.*/(.*)' '|' $a
       Note the quoted Shell metacharacters.

Diagnostics
       The command returns the following exit codes:

       0    The expression is neither null nor '0'.

       1    The expression is null or '0'.

       2    The expression is invalid.

See Also
       ed(1), sh(1), test(1)

																	   expr(1)
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