Command files when the output is assigned to a variable
Hi,
i'm posting this in the Solaris forum although maybe it should be better in the General unix forum, I'm formatting an output witht he following command:
How do I evaluate the result of a command assigned to a variable??
Example:
var1=`cmd`
rc=$?
rc will be the result of the assignment rather than cmd since it executes after. How do I evaluate the result of the command itself?
Cheers..:confused: (2 Replies)
Hi,
I want to check if a variable has a value assigned to it or not.
I can do following -
cat $Var > File1
if
then
echo "$Var has value"
else
echo "$Var is null"
fi
But I have to check for 3 Variables and I want to wrap it up in couple of unix statements.
Any... (3 Replies)
I am making of a script that will go through a couple of for loops and create file names based on the values in that loop, however the variable that combines everything is not getting assigned properly:
#! /bin/bash
for imod in K33_j1b_WS9_6
do
for emod in mb2A mb2C mb3A mb3C mb4A... (1 Reply)
I'm having a problem how to find the specific word in a file without using the word itself as a search but using the assigned variable which is the $passwd.. what command should I use to find the value of $passwd written in different script? how do I use the command to print the value in this... (7 Replies)
The requirement is, there is a log file which contains a huge data. i need to get a particular field out of it by searching with another field.
ex:
2011-03-28 13:00:07,423 : millis=231 q={ call get_data_account(?,?,?,?,?) }, params=
i need to search for the word "get_data_account" in file... (1 Reply)
I am trying to check whether a variable has been assigned on the command line or not.
Here is what I did:
#!/usr/bin/bash
if( $variable == '\0')
{
print "variable was not assigned"
exit
}
else
NF = 2 {print $1, ""}
exit
fi
awk -f question1.awk variable = 58 letters.txt.
So... (3 Replies)
I want to do 2 things in single line that is evaluating a command to get return code and store $2 of awk if the command exit code is 0.
eval "ade desc ${filename}@@/<branch_name> | grep Version | awk '{print $2}' 2>&1 1>/dev/null"
ret=$?
echo "$ret $val"
if
then
... (3 Replies)
Hi,
My command is getting stuck while running it.
observed that the grep command doesn't returned any data ($? was 1) and it failed.
This command is assigned into the variable and used in other command as script progresses. To continue the script output, i have to press ^C twice and script... (2 Replies)
Experts,
I'm having problems with the code below.
I'm trying to test $var2 for two different regexs.
I thought it could be done per below, but I'm getting the following error when running.
$ ./test.pl b fed50c0100****
Unescaped left brace in regex is deprecated, passed through in regex; marked... (2 Replies)
Discussion started by: timj123
2 Replies
LEARN ABOUT NETBSD
zfgrep
ZGREP(1) BSD General Commands Manual ZGREP(1)NAME
zgrep, zegrep, zfgrep -- print lines matching a pattern in gzip-compressed files
SYNOPSIS
zgrep [grep-flags] [--] pattern [files ...]
zegrep [grep-flags] [--] pattern [file ...]
zfgrep [grep-flags] [--] pattern [file ...]
DESCRIPTION
zgrep runs grep(1) on files or stdin, if no files argument is given, after decompressing them with zcat(1).
The grep-flags and pattern arguments are passed on to grep(1). If an -e flag is found in the grep-flags, zgrep will not look for a pattern
argument.
zegrep calls egrep(1), while zfgrep calls fgrep(1).
EXIT STATUS
In case of missing arguments or missing pattern, 1 will be returned, otherwise 0.
SEE ALSO egrep(1), fgrep(1), grep(1), gzip(1), zcat(1)AUTHORS
Thomas Klausner <wiz@NetBSD.org>
BSD December 28, 2003 BSD