Replacing part of a pattern in sed Post: 302487106

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Top Forums Shell Programming and Scripting Replacing part of a pattern in sed Post 302487106 by vnn on Tuesday 11th of January 2011 11:44:07 AM

01-11-2011

Registered User

There is no newline between the patterns<int>163</int> and <int>30</int>\n in your input request :

Code:

# cat ts1
web_request(abc,
"Method=null",
"TargetObjectId=/1",
BEGIN_ARGUMENTS,
"<timestamp>0</timestamp>\n <timeToLive>0</timeToLive>\n <headers>\n "
" <entry>\n <string>DDD</string>\n <string>"
"</string>\n </entry>\n <entry>\n <string>asnumber</string>\n "
" <string>345</string>\n </entry"
">\n <entry>\n <string>bsnumber</string>\n <string>378"
"</string>\n </entry>\n </headers>\n <operation>handleCall</"
"operation>\n <parameters>\n <int>163</int><int>30</int>\n "
" <string>CANCEL</string>\n <null/>\n <boolean>false</boolean>"
"\n </parameters>\n"
END_ARGUMENTS,
LAST);
}

What the input request should be:

Code:

web_request(abc, 
"Method=null", 
"TargetObjectId=/1", 
BEGIN_ARGUMENTS, 
"<timestamp>0</timestamp>\n <timeToLive>0</timeToLive>\n <headers>\n "
" <entry>\n <string>DDD</string>\n <string>"
"</string>\n </entry>\n <entry>\n <string>asnumber</string>\n "
" <string>345</string>\n </entry"
">\n <entry>\n <string>bsnumber</string>\n <string>378"
"</string>\n </entry>\n </headers>\n <operation>handleCall</"
"operation>\n <parameters>\n <int>163</int>\n <int>30</int>\n "
" <string>CANCEL</string>\n <null/>\n <boolean>false</boolean>"
"\n </parameters>\n" 
END_ARGUMENTS, 
LAST);

It is when I include that newline and a few spaces between <int>163</int> and <int>30</int>\n that the sed code does not work...

Thanks.

Moderator's Comments:

Please use code tags

Last edited by Scott; 01-11-2011 at 12:51 PM.. Reason: Code tags, please...

vnn

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