01-10-2011
The above command is not recursive, it's just displays the content of the directories
in the current directory (I mean, it's just like ls <directory_name>).
The pattern .[!.]* matches filenames the begin with a literal dot (.), followed by a character different from a dot,
followed by 0 or more characters of any type. The following * matches any number of non-dot characters characters.
10 More Discussions You Might Find Interesting
1. UNIX for Dummies Questions & Answers
I'm trying to figure out how to build a small shell script that will find old .shtml files in every /tgp/ directory on the server and delete them if they are older than 10 days...
The structure of the paths are like this:
/home/domains/www.domain2.com/tgp/
/home/domains/www.domain3.com/tgp/... (1 Reply)
Discussion started by: Neko
1 Replies
2. UNIX for Dummies Questions & Answers
what will the cmd below do?
ls *.3
1 members mentions that to seek all permutations and combinations of the mp3 extension ill have to use curly braces, {} and not, .
what then will do? (13 Replies)
Discussion started by: abhi
13 Replies
3. Shell Programming and Scripting
Just a quick question:
if I want to do a comparison with a wildcard in a shell script, do i just use '*'? Heres what I have:
elif ; then
continue
but that doesnt evaluate right. It tries to compare against the literal '/apps*' instead of anything that begins with '/apps' (2 Replies)
Discussion started by: rdudejr
2 Replies
4. Shell Programming and Scripting
Hi, I have this code to search all "cif" files using wildcard
for file in *.cif
do
grep "Uiso" $file | awk '{ print $3, $4, $5 }' > tet
done
I get this error
"grep: *.cif: No such file or directory"
Please where am I going wrong!!!
Thank you in advance (6 Replies)
Discussion started by: princessotes
6 Replies
5. Shell Programming and Scripting
Hi,
Can anyone help me how to use * in if statement.
File contains below
line1:a|b|c|Apple-RED|
line2:c|d|e|Apple-Green|
line3:f|g|h|Orange|
I need to find line by line 4th field contains 'Apple' or not.
Please help me at the earliest. (6 Replies)
Discussion started by: jam_prasanna
6 Replies
6. Shell Programming and Scripting
i have got heaps of files (.pdf, .txt and .doc) files in one folder, i am making a program in PERL that helps me find the files i want easier using shell wildcard,
something like this!!
print "Enter a pattern: (must be in )";
$input = <STDIN>;
if (The input is in and valid wildcard... (3 Replies)
Discussion started by: bshell_1214
3 Replies
7. Shell Programming and Scripting
I'm trying to make a small script to see if you say a specific word, in bash.
Here is my code so far :
if ]; then
echo "You typed Something Device Something"
fi
exit 0
It does not echo what it should, even if i type something along the lines of "random Device stuff"
Please help,... (2 Replies)
Discussion started by: DuskFall
2 Replies
8. Shell Programming and Scripting
Hi Experts,
I want to use ls in the below form:
ls -l *.{txt,TXT} (working fine)
but when i am declaring a variable,
VAR="*.{txt,TXT}"
ls -l $VAR is not working. Please help.
Thanks. (4 Replies)
Discussion started by: sugarcane
4 Replies
9. Shell Programming and Scripting
GNU grep with Oracle Linux 6.3
I want to grep for strings starting with the pattern ora and and having the words r2j in it. It should return the lines highlighted in red below.
But , I think I am not using wildcard for multiple characters correctly.
$ cat someText.txt
ora_pmon_jcpprdvp1... (3 Replies)
Discussion started by: kraljic
3 Replies
10. OS X (Apple)
CD_numb is AM017
this code:
set the_Firstcom_CD to (do shell script "ls -d '/volumes/audioNAS/Firstcom/Access Music/' ") & CD_numb
gives me this:
"/volumes/audioNAS/Firstcom/Access Music/AM017"
the item I am looking for is AM017Q.
I can get the "*" syntax right so it never finder... (7 Replies)
Discussion started by: sbrady
7 Replies
REGEXP(6) Games Manual REGEXP(6)
NAME
regexp - regular expression notation
DESCRIPTION
A regular expression specifies a set of strings of characters. A member of this set of strings is said to be matched by the regular
expression. In many applications a delimiter character, commonly bounds a regular expression. In the following specification for regular
expressions the word `character' means any character (rune) but newline.
The syntax for a regular expression e0 is
e3: literal | charclass | '.' | '^' | '$' | '(' e0 ')'
e2: e3
| e2 REP
REP: '*' | '+' | '?'
e1: e2
| e1 e2
e0: e1
| e0 '|' e1
A literal is any non-metacharacter, or a metacharacter (one of .*+?[]()|^$), or the delimiter preceded by
A charclass is a nonempty string s bracketed [s] (or [^s]); it matches any character in (or not in) s. A negated character class never
matches newline. A substring a-b, with a and b in ascending order, stands for the inclusive range of characters between a and b. In s,
the metacharacters an initial and the regular expression delimiter must be preceded by a other metacharacters have no special meaning and
may appear unescaped.
A matches any character.
A matches the beginning of a line; matches the end of the line.
The REP operators match zero or more (*), one or more (+), zero or one (?), instances respectively of the preceding regular expression e2.
A concatenated regular expression, e1e2, matches a match to e1 followed by a match to e2.
An alternative regular expression, e0|e1, matches either a match to e0 or a match to e1.
A match to any part of a regular expression extends as far as possible without preventing a match to the remainder of the regular expres-
sion.
SEE ALSO
awk(1), ed(1), sam(1), sed(1), regexp(2)
REGEXP(6)