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Full Discussion: Parsing log with sed problem
Top Forums Shell Programming and Scripting Parsing log with sed problem Post 302485651 by Chubler_XL on Wednesday 5th of January 2011 09:43:05 PM
Old 01-05-2011
How about this:

Code:
#!/bin/sh
sed -n \
    -e '/\-\-SELECT/  s/^.*\-\-//p' \         
    -e '/\-\-UPDATE/  s/^.*\-\-//p' \        
    -e '/\-\-DELETE/  s/^.*\-\-//p' \        
    -e '/#STMT#/      s/\].*//'     \
    -e '/#STMT#/      s/.*# \[//p' $1

-- Edit --
or, I think this is the sort of thing DGPickett was suggesting:
Code:
#!/bin/sh
sed -n \
    -e '/\-\-begin/d' \
    -e '/\-\-commit/d' \
    -e 's/^.*])\-\-//p' \
    -e '/#STMT#/s/^.*# \[\([^]]*\)].*/\1/p'


Last edited by Chubler_XL; 01-05-2011 at 11:04 PM..
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fixadd(3alleg4) 						  Allegro manual						   fixadd(3alleg4)

NAME
fixadd - Safe function to add fixed point numbers clamping overflow. Allegro game programming library. SYNOPSIS
#include <allegro.h> fixed fixadd(fixed x, fixed y); DESCRIPTION
Although fixed point numbers can be added with the normal '+' integer operator, that doesn't provide any protection against overflow. If overflow is a problem, you should use this function instead. It is slower than using integer operators, but if an overflow occurs it will set `errno' and clamp the result, rather than just letting it wrap. Example: fixed result; /* This will put 5035 into `result'. */ result = fixadd(itofix(5000), itofix(35)); /* Sets `errno' and puts -32768 into `result'. */ result = fixadd(itofix(-31000), itofix(-3000)); ASSERT(!errno); /* This will fail. */ RETURN VALUE
Returns the clamped result of adding `x' to `y', setting `errno' to ERANGE if there was an overflow. SEE ALSO
fixsub(3alleg4), fixmul(3alleg4), fixdiv(3alleg4) Allegro version 4.4.2 fixadd(3alleg4)
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