01-05-2011
Thanks for replying, but did not work - regular expression compile failed (bad class -- [],[^] or [)
Looks like the [ in front of the work backup... but...
Here is the exact data in the file that I need to grep:
123 full 129234532 123234122 1297 2123121 1231211 123121 rsync 0 0
124 incr 129232342 129452323 1232 2342322 1123232 112312 rsync 0 0
I need to know the data in front of the word FULL... that is the directory name that I need to cp or tar...
Thanks for replying...
---------- Post updated at 01:59 PM ---------- Previous update was at 11:22 AM ----------
After some research I believe I got it!!
awk '/full/ { print $1 } ' myfile
this finds the word full, then prints out the first column in the file, which happens to be the directory name in my case....
Now to pipe this output to a tar command to look for that directory name... done.
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ZGREP(1) General Commands Manual ZGREP(1)
NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO
grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)
ZGREP(1)