Sponsored Content
Top Forums Shell Programming and Scripting Arithmetic operation between columns using loop variable Post 302485418 by michaelrozar17 on Wednesday 5th of January 2011 07:32:12 AM
Old 01-05-2011
Quote:
Originally Posted by Surabhi_so_mh
I am doing like this:
Code:
for ((i=1; i<=3; i++))
do
  a=`echo "2*$i+2.561" | bc -l`   
  awk '{ printf"%.8f %.8f %.8f\n", ($1/a), $2, $3 }' infile >> out$i
done

but it seems variable a has to be defined within awk. how can I use i in it? Please help
To declare a variable within awk use -v option..so the above awk could be as
Code:
awk -v var="$a" '{ printf"%.8f %.8f %.8f\n", $1/var, $2, $3 }' infile >> out$i

 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Simple arithmetic operation

I have no idea why I can't get this to work, if anybody can help i would appreciate it. #!/bin/bash x=`cat counter.txt | wc -l` y= '$x / 7' printf "%d People have visited this page" $y :confused: (2 Replies)
Discussion started by: paladyn_2002
2 Replies

2. Shell Programming and Scripting

Help with arithmetic operation

I am using egrep to extract numbers from a file and storing them as variables in a script. But I am not able to do any arithmetic operations on the variables using "expr" because it stores them as char and not integers. Here is my code and the error I get. Any help will be appreciated. #!/bin/sh... (3 Replies)
Discussion started by: emjayshaikh
3 Replies

3. UNIX for Dummies Questions & Answers

arithmetic operation on two columns

Hi, All, I have a file, its content is as follows: 100 150 120 135 140 170 I want to insert a column, its content is determined by the difference between the two values in the same line, if the difference is less than 20, the new value is 1, otherwise is 0. after the operation, the... (1 Reply)
Discussion started by: Jenny.palmy
1 Replies

4. Shell Programming and Scripting

How to perform arithmetic operation on date

Hi all, I would appreciate if anyone knows how to perform adding to date. As for normal date, i can easily plus with any number. But when it comes to month end say for example 28 Jun, i need to perform a plus with number 3, it will not return 1 Jul. Thanks in advance for your help. (4 Replies)
Discussion started by: agathaeleanor
4 Replies

5. Shell Programming and Scripting

Arithmetic operation with awk

I have output like following in a file usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:23:58 usmtnz-dinfsi19 72 71 38 1199 1199 0.8 19:24:04 (9 Replies)
Discussion started by: fugitive
9 Replies

6. Shell Programming and Scripting

floating point arithmetic operation error

I am writing a script in zsh shell, it fetchs a number from a file using the awk command, store it as a variable, which in my case is a small number 0.62000. I want to change this number by multiplying it by 1000 to become 620.0 using the command in the script var2=$((var1*1000)) trouble is... (2 Replies)
Discussion started by: piynik
2 Replies

7. UNIX for Dummies Questions & Answers

Basic arithmetic operation with awk?

input: Name|Operation rec_10|1+2+2- Output: rec_10|1 Basically I am trying to calculate the result of "the path" in $3 where the operators follow the number and not preceding them like we normally do: rec_10: +1+2-2=1 But I realise (I am sure there is a good reason for that) that awk... (7 Replies)
Discussion started by: beca123456
7 Replies

8. Shell Programming and Scripting

Arithmetic operation in variable

Hi, Here is the script i try to perform arithmetic operation in two variables . git branch -r | while read brname ; do REV_COMMITS=`git rev-list --count $brname` echo "$brname has $REV_COMMITS" (( TOTAL = TOTAL + REV_COMMITS )) echo "in loop" $TOTAL done echo "total is " $TOTAL ... (3 Replies)
Discussion started by: greet_sed
3 Replies

9. Shell Programming and Scripting

Using awk to do arithmetic operation

Hi, I've this following text file FileVersion = 1.03 Filetype = meteo_on_curvilinear_grid TIME = 0 hours since 2016-10-03 12:00:00 +00:00 -6.855 -6.828 -6.801 -6.774 -6.747 -6.719 -6.691 -6.663 -6.634 -6.606 -6.577 -6.548 -6.519 -6.489 TIME = 0 hours since... (2 Replies)
Discussion started by: xisan
2 Replies

10. How to Post in the The UNIX and Linux Forums

How to get defined precision after arithmetic operation using syncsort?

I have to do some arithmetic operation on Field 8 which is calculated by Field 9/Field 7 Suppose i have data like : 0800123456|JAN|2017|JAN|2018|0800123456|0|0.0000|0.00| 0800234567|JAN|2017|JAN|2018|0800234567|4|2.5812|10.32| 0800666666|JAN|2017|JAN|2018|0800666666|2|1.7255|3.45|... (0 Replies)
Discussion started by: pumrao
0 Replies
IGAWK(1)							 Utility Commands							  IGAWK(1)

NAME
igawk - gawk with include files SYNOPSIS
igawk [ all gawk options ] -f program-file [ -- ] file ... igawk [ all gawk options ] [ -- ] program-text file ... DESCRIPTION
Igawk is a simple shell script that adds the ability to have ``include files'' to gawk(1). AWK programs for igawk are the same as for gawk, except that, in addition, you may have lines like @include getopt.awk in your program to include the file getopt.awk from either the current directory or one of the other directories in the search path. OPTIONS
See gawk(1) for a full description of the AWK language and the options that gawk supports. EXAMPLES
cat << EOF > test.awk @include getopt.awk BEGIN { while (getopt(ARGC, ARGV, "am:q") != -1) ... } EOF igawk -f test.awk SEE ALSO
gawk(1) Effective AWK Programming, Edition 1.0, published by the Free Software Foundation, 1995. AUTHOR
Arnold Robbins (arnold@skeeve.com). Free Software Foundation Nov 3 1999 IGAWK(1)
All times are GMT -4. The time now is 08:23 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy