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Full Discussion: string comparison not working inside while loop
Top Forums Shell Programming and Scripting string comparison not working inside while loop Post 302484432 by drl on Friday 31st of December 2010 06:22:17 AM
Old 12-31-2010
Hi.

I suggest you look at the content of the variable. Here are some methods:
Code:
#!/usr/bin/env bash

# @(#) s1	Demonstrate 3 ways to see value of string.

# Utility functions: print-as-echo, print-line-with-visual-space.
pe() { for i;do printf "%s" "$i";done; printf "\n"; }
pl() { pe;pe "-----" ;pe "$*"; }

f_status="Needs Checkout"

pl " Method 1: print bounded by some character to show whitespace:"
echo " f_status is :$f_status:"

pl " Method 2: use utility to show all characters:"
echo " f_status details:"
echo "$f_status" | od -bc

pl " Method 3: use shell to show details of operations:"
set -x
if [[ "${f_status}" == "Needs Checkout" ]]; then echo hello; fi

exit 0

producing:
Code:
% ./s1

-----
 Method 1: print bounded by some character to show whitespace:
 f_status is :Needs Checkout:

-----
 Method 2: use utility to show all characters:
 f_status details:
0000000 116 145 145 144 163 040 103 150 145 143 153 157 165 164 012
          N   e   e   d   s       C   h   e   c   k   o   u   t  \n
0000017

-----
 Method 3: use shell to show details of operations:
+ [[ Needs Checkout == \N\e\e\d\s\ \C\h\e\c\k\o\u\t ]]
+ echo hello
hello
+ exit 0

Good luck ... cheers, drl
 

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