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Top Forums Shell Programming and Scripting How to delete a huge number of files at a time Post 302484129 by Perderabo on Wednesday 29th of December 2010 10:53:13 PM
Old 12-29-2010
Quote:
Originally Posted by rdcwayx
give you some outputs, when deleting, so you can monitor the progress.

Code:
ls file???????.dat |while read file
do
  echo "Deleting file $file"
  rm $file
done

That is adding half a million fork() calls to a procedure that is already painfully long. I must advise against that. Once an hour or so he can count the remaining files using the command I gave. (Put the delete in the baxkground or use a second window.)
 

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DBSWISS(1)							   User Commands							DBSWISS(1)

NAME
dbSwiss - create DBM version of Swiss-Prot data SYNOPSIS
/usr/share/librg-utils-perl/dbSwiss [OPTIONS] /usr/share/librg-utils-perl/dbSwiss --datadir /data/swissprot --infile /data/swissprot/uniprot_sprot.dat /usr/share/librg-utils-perl/dbSwiss [--help] [--man] DESCRIPTION
dbSwiss creates DBM version of Swiss-Prot data. This procedure is to replace splitSwiss.pl. splitSwiss.pl saves Swiss-Prot records in separate files resulting in over 13 million relatively tiny files that take very long to create and rsync. dbSwiss instead saves each record into a DBM database that is optimized for fast retrieval. OPTIONS
-d, --datadir=path directory of database files, default: '/mnt/project/rost_db/data/swissprot' --debug --nodebug --first20 --nofirst20 process only first 20 records, for debugging --help -i, --infile=path Swiss-Prot data flatfile, default: '/mnt/project/rost_db/data/swissprot/uniprot_sprot.dat'. --man --quiet --noquiet do not print progress status --readback --noreadback read records back after storing and print them --table name of database table and consequently the base name of database files, default: 'dbswiss' --version -w, --workdir=path Optional working directory. Automatically created and removed if not defined. AUTHOR
Laszlo Kajan <lkajan@rostlab.org> 1.0.43 2011-11-28 DBSWISS(1)
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