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Top Forums Shell Programming and Scripting Count the number or row with same value in a column Post 302480416 by sQew on Tuesday 14th of December 2010 11:04:12 PM
Old 12-15-2010
Quote:
Originally Posted by R0H0N
Code:
cat inputfile | cut -f1 | uniq | while read line
do
count=`grep "$line" inputfile | wc -l`
if [ $count -gt 10 ] ; then
    mail -s "subject:more than 10" abc@abc.com
else
    mail -s "subject:less than 10" abc@abc.com
fi

Hi R0H0N,

Thanks for the reply, i tried to use your solution here but i think something is missing. On every condition i test, all email is use subject less than 10. Means that it pass the first conditions, i tried to put greater then 10,20,30,40 with same input file but same email coming into my email.

Furthermore, the email contains all lines and i need only line started with 196. What modification can be made on your code here?
Thanks

---------- Post updated at 12:03 PM ---------- Previous update was at 12:01 PM ----------

Quote:
Originally Posted by pludi
@R0H0N: calling uniq will squeeze together similar lines, thus reducing the reported vs. real number of lines matching. Also, UUOC

Simpler:
Code:
errors=$( awk '$1 == 196{total++} END{print total}' error_file )
if [ $errors -gt ]
then
     # use prefered mail sending tool here
fi

Hi Pludi,

I also tested your method, how ever it only printed the total amount of line with 196, ie:19 in this case. Anyway to make it more complete?

Thanks

---------- Post updated at 12:04 PM ---------- Previous update was at 12:03 PM ----------

Quote:
Originally Posted by rdcwayx
Code:
awk '{a[$1]++}
END{for (i in a) {if (a[i]>10) {c=(c=="")?i:c FS i}
                        else {b=(b=="")?i:b FS i}
                 }
       print "code than 10:", c |"mailx your@mail.com";
       print "code not than 10:", b|"mailx other@mail.com";
}' infile

Hi rdcwayx,

Thanks for the reply, however when i run this script it it prompt for syntax error on line 2,3.
 

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