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Top Forums Shell Programming and Scripting I want a count only when couple of value exist in each line of my source. Post 302479412 by elamurugu on Friday 10th of December 2010 02:48:10 PM
Old 12-10-2010
I want a count only when couple of value exist in each line of my source.

I have to get the count only if poc=4060 and loc=JPN ( basically I want to check both values exist then count the occurrences.)


disp0201.php?poc=4060&roc=1&ps=R&ooc=13&mjv=6&mov=5&rel=5&bod=155&oxi=2&omj=5&ozn=1&dav=20&cd=&daz=& drc=&mo=&sid=&lang=EN&loc=JPN

I have been trying like this
grep -c -E 'oc=70|pc=64150' samplelogs.log

tr -cs 'A-Za-z0-9=' '\n' < samplelogs.log | grep -c -E 'oc=70|pc=64150|rc=1'
but not seems to workout perfectly.

Help me on this..
Thanks
EM
 

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GREP(1) 						      General Commands Manual							   GREP(1)

NAME
grep - search a file for lines containing a given pattern SYNOPSIS
grep [-elnsv] pattern [file] ... OPTIONS
-e -e pattern is the same as pattern -c Print a count of lines matched -i Ignore case -l Print file names, no lines -n Print line numbers -s Status only, no printed output -v Select lines that do not match EXAMPLES
grep mouse file # Find lines in file containing mouse grep [0-9] file # Print lines containing a digit DESCRIPTION
Grep searches one or more files (by default, stdin) and selects out all the lines that match the pattern. All the regular expressions accepted by ed and mined are allowed. In addition, + can be used instead of * to mean 1 or more occurrences, ? can be used to mean 0 or 1 occurrences, and | can be used between two regular expressions to mean either one of them. Parentheses can be used for grouping. If a match is found, exit status 0 is returned. If no match is found, exit status 1 is returned. If an error is detected, exit status 2 is returned. SEE ALSO
cgrep(1), fgrep(1), sed(1), awk(9). GREP(1)
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