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Top Forums Shell Programming and Scripting extract characters from file name - script Post 302478860 by dragon.1431 on Thursday 9th of December 2010 05:13:00 AM
Old 12-09-2010
hi,
just curious ,
Code:
echo "samplefile1.f0633.bin" | sed 's/.*\.[a-z]*\([0-9][0-9]*\)\.[bin|cmp|enc]/\1/'

output :
Code:
0633in

i couldn't find the reason why i didn't get 0633 Smilie

Last edited by dragon.1431; 12-09-2010 at 06:20 AM.. Reason: corrected typo
 

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ZIP_NAME_LOCATE(3)					     Library Functions Manual						ZIP_NAME_LOCATE(3)

NAME
zip_name_locate - get index of file by name LIBRARY
libzip (-lzip) SYNOPSIS
#include <zip.h> int zip_name_locate(struct zip *archive, const char *fname, int flags); DESCRIPTION
The zip_name_locate function returns the index of the file named fname in archive. If archive does not contain a file with that name, -1 is returned. The are specified by or'ing the following values, or 0 for none of them. ZIP_FL_NOCASE Ignore case distinctions. ZIP_FL_NODIR Ignore directory part of file name in archive. RETURN VALUES
zip_name_locate returns the index of the file named fname or -1, if archive does not contain an entry of that name. ERRORS
The zip_name_locate function fails and sets the error information to ZIP_ER_NOENT if no entry of the name fname is found in the archive. If one of the arguments is invalid, the error information is set to ZIP_ER_INVAL. SEE ALSO
libzip(3), zip_get_name(3) AUTHORS
Dieter Baron <dillo@giga.or.at> and Thomas Klausner <tk@giga.or.at> NiH October 4, 2006 ZIP_NAME_LOCATE(3)
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