12-08-2010
find replace a pattern and following characters in a word
Suppose that I have a string "one:#red two:#yellow three:#gr'een four:#blu^e" and I want to replace the pattern :# and the following characters in the word with nothing. The output string should look "one two three four" How can I do this with sed.
Some points to consider (a) the last word in the sentence. (b) the first word in the sentence and (c) I am processing non-english text, so I have special characters '^ in it (d) lets assume the separator string :# are not special characters.
Many thanks in advance.
J.
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LEARN ABOUT MOJAVE
tcl_stringcasematch
Tcl_StringMatch(3) Tcl Library Procedures Tcl_StringMatch(3)
__________________________________________________________________________________________________________________________________________________
NAME
Tcl_StringMatch, Tcl_StringCaseMatch - test whether a string matches a pattern
SYNOPSIS
#include <tcl.h>
int
Tcl_StringMatch(str, pattern)
int
Tcl_StringCaseMatch(str, pattern, flags)
ARGUMENTS
const char *str (in) String to test.
const char *pattern (in) Pattern to match against string. May contain special characters from the set *?[].
int flags (in) OR-ed combination of match flags, currently only TCL_MATCH_NOCASE. 0 specifies a case-sensitive search.
_________________________________________________________________
DESCRIPTION
This utility procedure determines whether a string matches a given pattern. If it does, then Tcl_StringMatch returns 1. Otherwise
Tcl_StringMatch returns 0. The algorithm used for matching is the same algorithm used in the string match Tcl command and is similar to
the algorithm used by the C-shell for file name matching; see the Tcl manual entry for details.
In Tcl_StringCaseMatch, the algorithm is the same, but you have the option to make the matching case-insensitive. If you choose this (by
passing TCL_MATCH_NOCASE), then the string and pattern are essentially matched in the lower case.
KEYWORDS
match, pattern, string
Tcl 8.5 Tcl_StringMatch(3)