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Top Forums Shell Programming and Scripting Echo date variable from data input to a script Post 302478169 by iga3725 on Tuesday 7th of December 2010 09:40:16 AM
Old 12-07-2010
Echo date variable from data input to a script

Hi, I'm trying to make a script which you type the year, select the month and day and then create the date in the format 2010-12-7.
Code:
#!/bin/bash

dia () {
echo " Seleccione el dia:"
select file in 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27 28 29 30 31 Salir
do
case $file in
"1") d=1 ; fecha ;;
"2") d=2 ; fecha ;;
"3") d=3 ; fecha ;;
"4") d=4 ; fecha ;;
"5") d=5 ; fecha ;;
"6") d=6 ; fecha ;;
"7") d=7 ; fecha ;;
"8") d=8 ; fecha ;;
"9") d=9 ; fecha ;;
"10") d=10 ; fecha ;;
"11") d=11 ; fecha ;;
"12") d=12 ; fecha ;;
"13") d=13 ; fecha ;;
"14") d=14 ; fecha ;;
"15") d=15 ; fecha ;;
"16") d=16 ; fecha ;;
"17") d=17 ; fecha ;;
"18") d=18 ; fecha ;;
"19") d=19 ; fecha ;;
"20") d=20 ; fecha ;;
"21") d=21 ; fecha ;;
"22") d=22 ; fecha ;;
"23") d=23 ; fecha ;;
"24") d=24 ; fecha ;;
"25") d=25 ; fecha ;;
"26") d=26 ; fecha ;;
"27") d=27 ; fecha ;;
"28") d=28 ; fecha ;;
"29") d=29 ; fecha ;;
"30") d=30 ; fecha ;;
"31") d=31 ; fecha ;;
"Salir") exit 1;;
 *)
    echo "ERROR: Seleccione correctamente... "
    dia;;
esac
done
}

mes () {
echo " Seleccione el mes:"
select file in enero febrero marzo abril mayo junio julio agosto septiembre octubre noviembre diciembre Salir
do
case $file in
"enero") m=1 ; dia ;;
"febrero") m=2 ; dia ;;
"marzo") m=3 ; dia  ;;
"abril") m=4 ; dia  ;;
"mayo") m=5 ; dia  ;;
"junio") m=6 ; dia  ;;
"julio") m=7 ; dia  ;;
"agosto") m=8 ; dia  ;;
"septiembre") m=9 ; dia  ;;
"octubre") m=10 ; dia  ;;
"noviembre") m=11 ; dia  ;;
"diciembre") m=12 ; dia  ;;
"Salir") exit 1;;
 *)
    echo "ERROR: Seleccione correctamente... "
    mes;;
esac
done
}

anno () {
echo " Seleccione la anno, insertando las dos ultimas cifras:"
read yshort

if [[ $( echo $yshort | sed 's/^[-+0-9][0-9]*//' | wc -c ) -ne 1 ]]; then echo "ERROR: Introduzca correctamente dos caracteres numericos." && exit 1; fi

if [[ $( expr length $yshort) -ne 2 ]] ; then echo "ERROR: Introduzca SOLO dos caracteres" && exit 1 ;fi
Y=20$yshort
}

fecha () {
fecha=`echo " $Y-$m-$d"`
echo $fecha
exit 0
}

main () {

anno
mes
dia

}

main

The problem? Simple, I want to select the day regarding the month, I mean, to print 30 days if you selected the month of 30 days and so on.

Any help on how to change my script?
Thanks in advance.
 

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DATETIME.SETDATE(3)							 1						       DATETIME.SETDATE(3)

DateTime::setDate - Sets the date

       Object oriented style

SYNOPSIS
public DateTime DateTime::setDate (int $year, int $month, int $day) DESCRIPTION
Procedural style DateTime date_date_set (DateTime $object, int $year, int $month, int $day) Resets the current date of the DateTime object to a different date. PARAMETERS
o $object -Procedural style only: A DateTime object returned by date_create(3). The function modifies this object. o $year - Year of the date. o $month - Month of the date. o $day - Day of the date. RETURN VALUES
Returns the DateTime object for method chaining or FALSE on failure. CHANGELOG
+--------+---------------------------------------------------+ |Version | | | | | | | Description | | | | +--------+---------------------------------------------------+ | 5.3.0 | | | | | | | Changed the return value on success from NULL to | | | DateTime. | | | | +--------+---------------------------------------------------+ EXAMPLES
Example #1 DateTime.setDate(3) example Object oriented style <?php $date = new DateTime(); $date->setDate(2001, 2, 3); echo $date->format('Y-m-d'); ?> Procedural style <?php $date = date_create(); date_date_set($date, 2001, 2, 3); echo date_format($date, 'Y-m-d'); ?> The above examples will output: 2001-02-03 Example #2 Values exceeding ranges are added to their parent values <?php $date = new DateTime(); $date->setDate(2001, 2, 28); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 2, 29); echo $date->format('Y-m-d') . " "; $date->setDate(2001, 14, 3); echo $date->format('Y-m-d') . " "; ?> The above example will output: 2001-02-28 2001-03-01 2002-02-03 SEE ALSO
DateTime.setISODate(3), DateTime.setTime(3). PHP Documentation Group DATETIME.SETDATE(3)
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