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Full Discussion: Date and time difference
Top Forums Shell Programming and Scripting Date and time difference Post 302477962 by RahulJoshi on Monday 6th of December 2010 10:26:59 PM
Old 12-06-2010
set a=3
set D1="5/21/2010 9:14:00 AM"
set D2="5/24/2010 7:23:00 AM"
set DDM=$((($(date -d "$D2" +%s)-$(date -d "$D1" +%s))/60))
Variable syntax
printf "%s:%02d\n" $((DDM/60)) $((DDM%60))
Variable syntax

why not working
 

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SWAPBDDVAR(3)							   BDD FUNCTIONS						     SWAPBDDVAR(3)

NAME
swapbddvar - swaps two contiguous variables. ORIGIN
This software belongs to the ALLIANCE CAD SYSTEM developed by the ASIM team at LIP6 laboratory of Universite Pierre et Marie CURIE, in Paris, France. Web : http://asim.lip6.fr/recherche/alliance/ E-mail : alliance-users@asim.lip6.fr SYNOPSYS
#include "bdd101.h" void swapbddvar( BddSystem, Variable ) bddsystem *BddSystem; bddvar Variable; PARAMETERS
BddSystem The bdd system. Variable The variable to swap. DESCRIPTION
swapbddvar swaps the variable number Variable with the variable number Variable + 1, in the bdd system BddSystem. If a null pointer is given, the default bdd system is used. This function is usefull for the bdd nodes reordering. RETURN VALUE
swapbddvar returns nothing. ERRORS
"variable xxx out of range, error !" The Variable and Variable + 1, must be valid variables number. EXAMPLE
#include "bdd101.h" bddsystem *BddSystem; bddnode *BddNode1; bddnode *BddNode2; BddSystem = createbddsystem( 100, 1000, 100, 50000 ); BddNode1 = addbddvar( (bddsystem *)0, 0 ); BddNode2 = addbddvar( (bddsystem *)0, 0 ); swapbddvar( (bddsystem *)0, 0 ); destroybddsystem( (bddsystem *)0 ); SEE ALSO
bdd(1) BUG REPORT
This tool is under development at the ASIM department of the LIP6 laboratory. We need your feedback to improve documentation and tools. ASIM
/LIP6 October 1, 1997 SWAPBDDVAR(3)
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