without using ls, just using echo so purely pattern matching
I can say echo */ <-- lists directories
but how would I match files? surely something like *!/ or * but neither work ?
it seems like there isn't much that I can put in but surely i should be able to put any ascii... (1 Reply)
Hi folks,
I need to stop printing a new line after echoing a string in KSH. i know bash provides
echo -n "string"
what is the ksh equivalent for this ? (3 Replies)
Hello,
I have lib file which contain a function that get text to print on screen by echo command.
Several scripts are inculde this lib and use this function.
Each one of them is written in different shell language (sh ksh & bash).
This causing some issues when using backslash charater as... (4 Replies)
Hi all,
Basically Im trying to put the current time in a script in BASH. Tried the watch command, but its not really what I want.
I will have lots of things in this script, current date and time being just a few).
Any ideas? (4 Replies)
Why does echo supress line breaks in bash?
I'm working on a script that starts like this:
words=`sort list.txt | uniq`
echo $words | wc -l
I need to number the lines and then do other stuff. I'd use jot, but it's not installed, so I hope I can get seq to do what I want. But first I need to... (2 Replies)
Newbie to bash here. I think this is fairly simple, but I have searched and cannot figure it out. In the code below, I am searching an array for an IP address, and then printing the IP address if found. However, I would like to print the actual variable found such as 2.2.2.2=2, but cannot figure... (1 Reply)
Hi,
I have a problem with passing a echo output into a variable in bash
file='1990.tar'
NAME='echo $file | cut -d '.' -f1';
echo $NAME
the result is
echo $file | cut -d . -f1
however with this one,#!/bin/bash
file='1990.tar'
echo $file | cut -d '.' -f1
the result is what I... (2 Replies)
Hi, I am trying to make a script to manage log. I want to write the name of the .gz I moved and the date :
for i in `ls $replog/*.gz`
do
echo " $i "
`echo $i date +%d:%m:%Y`
`echo $datee `>> $replog/mrnet.log
mv $i /var/log/vieux-logs
done
I need to echo... (10 Replies)
I'm trying to echo the release version of some of our Linux servers. Typically I do these types of things by "catting" a text file with the host names, "ssh-ing" to the host and running my string.
This is what I've written
for i in `cat versions.txt` ; do echo $i ; ssh $i cat /etc/issue |... (5 Replies)
I am writing a bash script that automatically generates a macro program.
I want to have an echo on multiple lines and getting an error
/home/chaos/instru-correct.sh: line 309: command line is: command not found
I am using
echo "# The general synopsis of the $mfl" \
... (2 Replies)
Discussion started by: kristinu
2 Replies
LEARN ABOUT MOJAVE
started
started(7) Miscellaneous Information Manual started(7)NAME
started - event signalling that a job is running
SYNOPSIS
started JOB=JOB INSTANCE=INSTANCE [ENV]...
DESCRIPTION
The started event is generated by the Upstart init(8) daemon when an instance of a job has finished starting and is now running. The JOB
environment variable contains the job name, and the INSTANCE environment variable contains the instance name which will be empty for sin-
gle-instance jobs.
init(8) emits this event as an informational signal, services and tasks started or stopped by this event will do so in parallel with other
activity. It is typically combined with the stopping(7) event by services declaring a dependency.
Job configuration files may use the export stanza to export environment variables from their own environment into the started event. See
init(5) for more details.
EXAMPLE
A service that wishes to depend on another service might use:
start on started apache
stop on stopping apache
A task that must be run after another task or service has been started might use:
start on started postgresql
SEE ALSO starting(7)stopping(7)stopped(7)init(5)Upstart 2009-07-09 started(7)