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Full Discussion: Difference in date
Top Forums Shell Programming and Scripting Difference in date Post 302477141 by rbatte1 on Friday 3rd of December 2010 10:39:43 AM
Old 12-03-2010
Difference in date

Dear all,

I fancy that I'm pretty competent in ksh, but I have someone on HP-UX wanting me to script up a simple interface to handle user alterations rather than giving them high privileges to run up SAM. This is all fairly straightforward, but I'm stuck on an epoch date issue.

When we have a short-term contractor, we have to set an expiry date on the account. Looking and the manual pages for usermod it gives me the syntax and I have tested it all out just fine, but the parameters it requires is for number of days in the future that the account will expire, yet my operative wants to key in a date.

I need to be able to get the difference in days between today and the date given - a simple current_date minus target_date in format yyyymmdd will tell me if the target date is in the past, but how can I do this to count the days in between?

Preference is for ksh, but I guess perl may be acceptable, especially as I found a lovely routine on here for going the other way that I have embedded in a ksh script:-
Code:
perl -e 'print scalar localtime $ARGV[0],"\n" ' $seconds_since_epoch

I've seen various suggestions, but all for some wild perl or C but I'd prefer to understand what the code is saying because someone will no doubt ask me later on! There is a neat suggestion of
Code:
perl -e 'use Time::Local; print timelocal("00","00","00","01","01","2000"),"\n";'

which I can get to work just fine on AIX, but HP-UX gives me the response:-
Quote:
Can't locate Time/Local.pm in @INC (@INC contains: /opt/perl5/lib/5.00502/PA-RISC1.1 /opt/perl5/lib/5.00502 /opt/perl5/lib/site_perl/5.005/PA-RISC1.1 /opt/perl5/lib/site_perl/5.005 .) at -e line 1.
BEGIN failed--compilation aborted at -e line 1
I think that this means that there is a library not installed or in the path. I also don't really know perl at all, but need to tweak it to accept a variable as in the first example.

Of course, the plan is to have a little stub of code that I can shovel my date into (time will just be midnight to make it easy) and get "seconds-from-epoch". After that, I can take one from the other and convert back with the perl above.

It's a shame that date +%s is not an option.

I had considered moving the timezone forwards and counting how many days to step, but it's hardly good code to do it like that, kicking up stacks more processes and possibly taking a while to run if the date in question is perhaps 18 months away.

Any suggestions?


Many thanks, in advance,
Robin
 

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lchage(8)						      System Manager's Manual							 lchage(8)

NAME
lchage - Display or change user password policy SYNOPSIS
lchage [OPTION]... user DESCRIPTION
Displays or allows changing password policy of user. OPTIONS
-d, --date=days Set the date of last password change to days after Jan 1 1970. -E, --expire=days Set the account expiration date to days after Jan 1 1970. Set days to -1 to disable account expiration. -i, --interactive Ask all questions when connecting to the user database, even if default answers are set up in libuser configuration. -I, --inactive=days Disable the account after days after password expires (after the user user is required to change the password). -l, --list Only list current user's policy and make no changes. -m, --mindays=days Require at least days days between password changes. Set days to 0 to disable this checking. -M, --maxdays=days Require changing the password after days since last password change. Set days to 99999 to disable this checking. -W, --warndays=days Start warning the user days before password expires (before the user is required to change the password). EXIT STATUS
The exit status is 0 on success, nonzero on error. libuser Jan 12 2005 lchage(8)
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