12-01-2010
ok, thanks. One more thing, I am not familiar with the match() function and I'm not sure if I'm supposed to use it, is there another way of getting a[1] and a[2]?
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LEARN ABOUT CENTOS
std::rel_ops
std::rel_ops(3) Library Functions Manual std::rel_ops(3)
NAME
std::rel_ops -
SYNOPSIS
Functions
template<class _Tp > bool operator!= (const _Tp &__x, const _Tp &__y)
template<class _Tp > bool operator<= (const _Tp &__x, const _Tp &__y)
template<class _Tp > bool operator> (const _Tp &__x, const _Tp &__y)
template<class _Tp > bool operator>= (const _Tp &__x, const _Tp &__y)
Detailed Description
The generated relational operators are sequestered here.
Function Documentation
template<class _Tp > bool std::rel_ops::operator!= (const _Tp &__x, const _Tp &__y) [inline]
Defines != for arbitrary types, in terms of ==.
Parameters:
__x A thing.
__y Another thing.
Returns:
__x != __y
This function uses == to determine its result.
Definition at line 87 of file stl_relops.h.
template<class _Tp > bool std::rel_ops::operator<= (const _Tp &__x, const _Tp &__y) [inline]
Defines <= for arbitrary types, in terms of <.
Parameters:
__x A thing.
__y Another thing.
Returns:
__x <= __y
This function uses < to determine its result.
Definition at line 113 of file stl_relops.h.
template<class _Tp > bool std::rel_ops::operator> (const _Tp &__x, const _Tp &__y) [inline]
Defines > for arbitrary types, in terms of <.
Parameters:
__x A thing.
__y Another thing.
Returns:
__x > __y
This function uses < to determine its result.
Definition at line 100 of file stl_relops.h.
template<class _Tp > bool std::rel_ops::operator>= (const _Tp &__x, const _Tp &__y) [inline]
Defines >= for arbitrary types, in terms of <.
Parameters:
__x A thing.
__y Another thing.
Returns:
__x >= __y
This function uses < to determine its result.
Definition at line 126 of file stl_relops.h.
Author
Generated automatically by Doxygen for libstdc++ from the source code.
libstdc++ Tue Jun 10 2014 std::rel_ops(3)