Hi all,
i have the following string as input :
"<iframe src="http://abcdef.com/asd/aaa/awerftya0480000008ave/direct;wi.120;hi.600/01?page=" frameborder="0" scrolling="no" marginheight="0" marginwidth="0" topmargin="0" leftmargin="0" allowtransparency="true" width="120" height="600">
<script... (1 Reply)
Hi,
Suppose I have the following text in a file.
ORA-00942: table or view does not exist
ORA-01555: snapshot too old: rollback segment number string with name "string"
too small
Is there any way I can list all the text that starts only with 'ORA-'?
Or there any grep command that can... (7 Replies)
Hi,
I have a file with rows of text like so :
E100005568374098100000015667
D100005568374032000000112682
H100005228374060800000002430
I need to grab just the last digits(bolded) of each line without the proceeding text/numbers.
Thanks (5 Replies)
Hi,
i am just gettin exposed to UNIX.
Could anyone of u help me out with dis problem..?
i have a variable 'act' which has the value as follows,
echo $act gives -0- -0- -----0---- 2008-06-04 -0- -0-
echo "$act" | awk '{print ($act)}'
gives,
-0-
-0-
-----0----
2008-06-04
-0-
-0-
I... (2 Replies)
i have a file that contains a pattern like this:
ajay 1234 newyork available
kumar 2345 denver
singh 2345 newyork
ajay 3456 denver
kumar 3456 newyork
singh 3456 delhi available
ajay 4567 miami
kumar 4567 miami
singh 4567 delhi
i want to search for each line... (5 Replies)
First of all I am VERY new to this so bare with me and try and explain everything even if it seems simple.
Basically I want to read a line of text from a html file. See if the line of text has a certain string in it. copy an unknown number of characters (the last 4 characters wiil be ".jpg" the... (1 Reply)
Hi All,
Pls help me out on the below,
05 LAMSZ201-ZM-MEMO2-DATE02-5 PIC X(10).
05 LAMSZ201-ZM-MEMO2-AMT02-5 PIC S9(13)V99.
05 LAMSZ201-ZM-MEMO2-TYPE02-6 PIC XXX.
05 LAMSZ201-ZM-MEMO2-DATE02-6 PIC X(10).
05 ... (2 Replies)
Hello
Could you help with small script:
How to split string X1 into 3 string
String X1 can have 1 or many strings
X1='A1:B1:C1:D1:A2:B2:C2:D2:A3:B3:C3:D3'
This is output which I want to have:
Z1='A1:B1:C1:D1'
Z2='A2:B2:C2:D2'
Z3='A3:B3:C3:D3' (5 Replies)
i have something like this...
echo "teCertificateId" | awk -F'Id' '{ print $1 }' | awk -F'te' '{ print $2 }'
Certifica
the awk should remove 'te' only if it is present at the start of the string.. anywhere else it should ignore it.
expected output is
Certificate (7 Replies)
I'm making a little game in Perl, and I am trying to remove the first instance of a character in an arbitrary string. For example, if the string is
"cupcakes"and the user enters another string that contains letters from "cupcake" e.g:
"sake"the original string will now look like this (below)... (3 Replies)
Discussion started by: whyte_rhyno
3 Replies
LEARN ABOUT DEBIAN
xcalpr
XCALPR(1) General Commands Manual XCALPR(1)NAME
xcalpr - print xcal calendar entries
SYNTAX
xcalpr [ -c ][ -x ][ -f file ][ -d dir ][ -u user ][ date-spec ]
DESCRIPTION
Xcalpr prints the contents of the xcal files. It is intended to be used in situations when you have no access to an X screen. It can also
be used to generate entries for the standard UNIX calendar program.
With no arguments, it prints any entries that exist for the next seven days. The program also reads the contents of the seven daily files
and prints them at the appropriate point in the output stream. Each line in the output is preceded by the day of the week, the day of the
month, the month and the year.
Xcalpr can be given a date specification to select months and years. If the date spec consists of just a year number, then all the data
for that year is printed. For example:
xcalpr 1994
will print all the data for 1994. Several years can be specified.
If you give the name of a month, then the data for that month in the current year will be printed. If the month is in the past, then the
data for that month next year will be printed. For example, if
xcalpr oct jan
is typed in August, xcalpr will print October in the current year and January next year.
You can select a particular year by adding the number after any months that you need printing:
xcalpr oct nov 1994
will print October and November in 1994.
There are a couple of special `month' names. The name rest will print the data for the rest of the month, starting tomorrow. The rest
argument is not recognised if you give a year as a parameter. If tomorrow happens to be the first day of the next month, then all the data
for next month will be printed. The name next prints all the data for next month.
OPTIONS
The -c option causes xcalpr to output lines suitable for input to the standard UNIX calendar program.
The -d switch is followed by a directory name and specifies an alterative location for your Calendar directory. Your home directory is
prepended if the name doesn't start with a slash or a dot.
The -f option is followed by a file name and xcalpr will write it's output to that file, rather than standard output.
The -u option is followed by a user name and dumps their calendar files rather than yours.
The -x option makes xcalev operate with Calendar files that are compatible with the xcalendar program.
FILES
$HOME/Calendar/*
xc<dd><Mon><Year> A data file is day, Month in three letter format and the year.
xy<Year> A year directory.
xw<Day> A data file for the weekly code, one per day.
SEE ALSO xcal(1), xcalev(1), xcal_cal(1)AUTHOR
Copyright 1993 by Peter Collinson, Hillside Systems All rights reserved.
This product includes software developed by the University of California, Berkeley and its contributors.
X Version 11 R5 October 1993 XCALPR(1)