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Full Discussion: Question about getopts
Top Forums Shell Programming and Scripting Question about getopts Post 302471817 by BeefStu on Monday 15th of November 2010 09:06:21 AM
Old 11-15-2010
Never been a big fan of getopt in KSH, its very limited. What happens if
you have an option that you want to use the same letter for?

For example, db_id and db_password. You can't use -d for both of them right.

Therefore, I take advantage of KSH and do something like this that lets
you pass in more descriptive option names. Note, case does not make a
difference if you code like this.

Code:
 
while(($#))
do
   case $1 in
       -+([dD]*(b_id|B_ID)))
         shift
         DB_ID=$1
         ;;
       -+([dD]*(b_pass|B_PASS)))
         shift
         DB_PASS=$1
         ;;
    -+([fF]*(lag|LAG)))
          shift
          let flag_passed=1
         ;;
       -+([iI]*(nfo|NFO)))
         usage
         return 0
         ;;
      *)
         shift ;;
   esac
done

This allows you to call your script like this

script-name -db_id xxx -db_password mypassword parm1 parm2 .....

Note if you don't want to pass a variable and set a flag only look at -flag
This User Gave Thanks to BeefStu For This Post:
 

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GETOPT(1)						    BSD General Commands Manual 						 GETOPT(1)

NAME
getopt -- parse command options SYNOPSIS
args=`getopt optstring $*` set -- `getopt optstring $*` DESCRIPTION
getopt is used to break up options in command lines for easy parsing by shell procedures, and to check for legal options. [Optstring] is a string of recognized option letters (see getopt(3)); if a letter is followed by a colon, the option is expected to have an argument which may or may not be separated from it by white space. The special option ``--'' is used to delimit the end of the options. getopt will place ``--'' in the arguments at the end of the options, or recognize it if used explicitly. The shell arguments ($1, $2, ...) are reset so that each option is preceded by a ``-'' and in its own shell argument; each option argument is also in its own shell argument. getopt should not be used in new scripts; use the shell builtin getopts instead. EXAMPLES
The following code fragment shows how one might process the arguments for a command that can take the options [a] and [b], and the option [c], which requires an argument. args=`getopt abc: $*` if [ $? -ne 0 ]; then echo 'Usage: ...' exit 2 fi set -- $args while [ $# -gt 0 ]; do case "$1" in -a|-b) flag=$1 ;; -c) carg=$2; shift ;; --) shift; break ;; esac shift done This code will accept any of the following as equivalent: cmd -acarg file file cmd -a -c arg file file cmd -carg -a file file cmd -a -carg -- file file IEEE Std 1003.2 (``POSIX.2'') mandates that the sh(1) set command return the value of 0 for the exit status. Therefore, the exit status of the getopt command is lost when getopt and the sh(1) set command are used on the same line. The example given is one way to detect errors found by getopt. DIAGNOSTICS
getopt prints an error message on the standard error output when it encounters an option letter not included in [optstring]. SEE ALSO
sh(1), getopt(3) HISTORY
Written by Henry Spencer, working from a Bell Labs manual page. Behavior believed identical to the Bell version. BUGS
Whatever getopt(3) has. Arguments containing white space or embedded shell metacharacters generally will not survive intact; this looks easy to fix but isn't. The error message for an invalid option is identified as coming from getopt rather than from the shell procedure containing the invocation of getopt; this again is hard to fix. The precise best way to use the set command to set the arguments without disrupting the value(s) of shell options varies from one shell ver- sion to another. BSD
November 28, 2009 BSD
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