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Full Discussion: Suppressing a message from being displayed
Top Forums Shell Programming and Scripting Suppressing a message from being displayed Post 302471363 by vpv0002 on Friday 12th of November 2010 02:54:55 PM
Old 11-12-2010
Suppressing a message from being displayed
I have a script which checks for *.txt files in a particular directory and if no files were found then it goes into sleep for 10 secs and looks back for files again and if any files were found then the script does some processing with the files found, which is my requirement too.
Code:
FILE_EXISTS=`ls ${INPUT_DIR}/*.txt | wc -l`
if [ $FILE_EXISTS -eq 0 ];
then
echo "No file found hence sleeping for 10 secs..."
sleep 10;
continue;
fi

but when ever no files were found a message saying
Code:
 ls: 0653-341 The file /home/sys/*.done does not exist.

Is being displayed which I do not want to be displayed. So I used
Code:
 >/dev/null 2>&1

in the script as below
Code:
FILE_EXISTS=`ls ${INPUT_DIR}/*.txt >/dev/null 2>&1 | wc -l`
if [ $FILE_EXISTS -eq 0 ];
      then
      echo "No file found hence sleeping for 10 secs..."
      sleep 10;
      continue;
fi

now the message is not being displayed but even if files exists in the directory, the file count is not being assigned to the variable FILE_EXISTS. Doing so the script does not go further to do the required file processing but instead it still goes into sleep for 10 secs. Could any one please suggest any correction which needs to be made to my script.
 

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