Sponsored Content
Full Discussion: help with awk
Top Forums UNIX for Dummies Questions & Answers help with awk Post 302470265 by iluvsushi on Tuesday 9th of November 2010 03:39:29 PM
Old 11-09-2010
help with awk

hi i have multiple rows of several outputs.
Code:
find: ./filename: Permission denied

i want to suppress the rows which say permission denied.

i was thinking of using awk for this
Code:
command | awk '( $3 != Permission denied) '

and it doesn't work. my skills are just novice level in sed, awk and any help would be really helpful. thanks.

---------- Post updated at 12:39 PM ---------- Previous update was at 12:33 PM ----------

my output sorta looks like this,
Code:
find: ./hmwk8: Permission denied
./.bashrc.sample

so i don't know what field Permission denied is in 2nd or 3rd but still does not work.

Last edited by Scott; 11-09-2010 at 04:43 PM.. Reason: Please use code tags
 

10 More Discussions You Might Find Interesting

1. Shell Programming and Scripting

Awk problem: How to express the single quote(') by using awk print function

Actually I got a list of file end with *.txt I want to use the same command apply to all the *.txt Thus I try to find out the fastest way to write those same command in a script and then want to let them run automatics. For example: I got the file below: file1.txt file2.txt file3.txt... (4 Replies)
Discussion started by: patrick87
4 Replies

2. Shell Programming and Scripting

scripting/awk help : awk sum output is not comming in regular format. Pls advise.

Hi Experts, I am adding a column of numbers with awk , however not getting correct output: # awk '{sum+=$1} END {print sum}' datafile 2.15291e+06 How can I getthe output like : 2152910 Thank you.. # awk '{sum+=$1} END {print sum}' datafile 2.15079e+06 (3 Replies)
Discussion started by: rveri
3 Replies

3. Shell Programming and Scripting

awk: assign variable with -v didn't work in awk filter

I want to filter 2nd column = 2 using awk $ cat t 1 2 2 4 $ VAR=2 #variable worked in print $ cat t | awk -v ID=$VAR ' { print ID}' 2 2 # but variable didn't work in awk filter $ cat t | awk -v ID=$VAR '$2~/ID/ { print $0}' (2 Replies)
Discussion started by: honglus
2 Replies

4. Shell Programming and Scripting

Problem with awk awk: program limit exceeded: sprintf buffer size=1020

Hi I have many problems with a script. I have a script that formats a text file but always prints the same error when i try to execute it The code is that: { if (NF==17){ print $0 }else{ fields=NF; all=$0; while... (2 Replies)
Discussion started by: fate
2 Replies

5. Shell Programming and Scripting

Comparison and editing of files using awk.(And also a possible bug in awk for loop?)

I have two files which I would like to compare and then manipulate in a way. File1: pictures.txt 1.1 1.3 dance.txt 1.2 1.4 treehouse.txt 1.3 1.5 File2: pictures.txt 1.5 ref2313 1.4 ref2345 1.3 ref5432 1.2 ref4244 dance.txt 1.6 ref2342 1.5 ref2352 1.4 ref0695 1.3 ref5738 1.2... (1 Reply)
Discussion started by: linuxkid
1 Replies

6. Shell Programming and Scripting

awk command to compare a file with set of files in a directory using 'awk'

Hi, I have a situation to compare one file, say file1.txt with a set of files in directory.The directory contains more than 100 files. To be more precise, the requirement is to compare the first field of file1.txt with the first field in all the files in the directory.The files in the... (10 Replies)
Discussion started by: anandek
10 Replies

7. Shell Programming and Scripting

HELP with AWK one-liner. Need to employ an If condition inside AWK to check for array variable ?

Hello experts, I'm stuck with this script for three days now. Here's what i need. I need to split a large delimited (,) file into 2 files based on the value present in the last field. Samp: Something.csv bca,adc,asdf,123,12C bca,adc,asdf,123,13C def,adc,asdf,123,12A I need this split... (6 Replies)
Discussion started by: shell_boy23
6 Replies

8. Shell Programming and Scripting

Passing awk variable argument to a script which is being called inside awk

consider the script below sh /opt/hqe/hqapi1-client-5.0.0/bin/hqapi.sh alert list --host=localhost --port=7443 --user=hqadmin --password=hqadmin --secure=true >/tmp/alerts.xml awk -F'' '{for(i=1;i<=NF;i++){ if($i=="Alert id") { if(id!="") if(dt!=""){ cmd="sh someScript.sh... (2 Replies)
Discussion started by: vivek d r
2 Replies

9. Shell Programming and Scripting

Pass awk field to a command line executed within awk

Hi, I am trying to pass awk field to a command line executed within awk (need to convert a timestamp into formatted date). All my attempts failed this far. Here's an example. It works fine with timestamp hard-codded into the command echo "1381653229 something" |awk 'BEGIN{cmd="date -d... (4 Replies)
Discussion started by: tuxer
4 Replies

10. Shell Programming and Scripting

awk output yields error: awk:can't open job_name (Autosys)

Good evening, Im newbie at unix specially with awk From an scheduler program called Autosys i want to extract some data reading an inputfile that comprises jobs names, then formating the output to columns for example 1. This is the inputfile: $ more MapaRep.txt ds_extra_nikira_usuarios... (18 Replies)
Discussion started by: alexcol
18 Replies
PAM_ACCT_MGMT(3)						 Linux-PAM Manual						  PAM_ACCT_MGMT(3)

NAME
pam_acct_mgmt - PAM account validation management SYNOPSIS
#include <security/pam_appl.h> int pam_acct_mgmt(pam_handle_t *pamh, int flags); DESCRIPTION
The pam_acct_mgmt function is used to determine if the users account is valid. It checks for authentication token and account expiration and verifies access restrictions. It is typically called after the user has been authenticated. The pamh argument is an authentication handle obtained by a prior call to pam_start(). The flags argument is the binary or of zero or more of the following values: PAM_SILENT Do not emit any messages. PAM_DISALLOW_NULL_AUTHTOK The PAM module service should return PAM_NEW_AUTHTOK_REQD if the user has a null authentication token. RETURN VALUES
PAM_ACCT_EXPIRED User account has expired. PAM_AUTH_ERR Authentication failure. PAM_NEW_AUTHTOK_REQD The user account is valid but their authentication token is expired. The correct response to this return-value is to require that the user satisfies the pam_chauthtok() function before obtaining service. It may not be possible for some applications to do this. In such cases, the user should be denied access until such time as they can update their password. PAM_PERM_DENIED Permission denied. PAM_SUCCESS The authentication token was successfully updated. PAM_USER_UNKNOWN User unknown to password service. SEE ALSO
pam_start(3), pam_authenticate(3), pam_chauthtok(3), pam_strerror(3), pam(7) Linux-PAM Manual 06/04/2011 PAM_ACCT_MGMT(3)
All times are GMT -4. The time now is 05:21 PM.
Unix & Linux Forums Content Copyright 1993-2022. All Rights Reserved.
Privacy Policy