Hi,
I have a shell script with an ambedded awk script.
i need to pass a script variable to the awk script.
Please help.
Thanks in advance
Himani (3 Replies)
Hey Guys
from the below script what I understood is we are sending the the first parameter as input to the main (){} file
main > $LOGFILE 2>&1
but can we send two or three parameter as input to this main file as
main > $LOGFILE 2>&1 2>&2 like this
Can any one plz help I need to writ a... (0 Replies)
Hello experts,
can I return a value from gawk to a shell script ?
My script as follows,
#Here I want the num value to shell script so that I can use later
gawk '
{
split($0,num,",");
print num
}'
gawk -v no=$number '{print no}'
file1
... (3 Replies)
Hello Experts,
Actually I was searching for a solution here in this forum , but didn't get what exactly I want . Is this possible to do in awk ?
I am trying to do some thing like below in ksh script . Upto my knowledge I can pass shell script to awk with "-v " option.
But I... (3 Replies)
I have a working and tested AWK script that removes duplicates from an input file and generates an output file without the duplicates.
I had help from my other post to develop it:
... (3 Replies)
Hi,
I basically have 2 shell scripts.
One is a shell script will get the variable value from the user. The variable is nothing but the IP of the remote system.
Another shell script is a script that does the job of connecting to the remote system using ssh. This uses a expect utility in turn.
... (2 Replies)
Why does this work
for myfile in `find . -name "R*VER" -mtime +1`
do
SHELLVAR=`grep ^err $myfile || echo "No error"`
ECHO $SHELLVAR
done
and outputs
No error
err ->BIST Login Fail 3922 err
No error
err ->IR Remote Key 1 3310 err
But... (2 Replies)
Discussion started by: alan
2 Replies
8. Post Here to Contact Site Administrators and Moderators
Variable I have in my shell script
diff=$1$2.diff
id=$2
new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk -F'~' ''$2 == "$id"' {print $0}' > $new
I could see value of $id is not passing to the awk... (0 Replies)
I have a shell script (.sh) and I want to pass a parameter value to the awk command but I am getting exception, please assist.
diff=$1$2.diff
id=$2 new=new_$diff
echo "My id is $1"
echo "I want to sync for user account $id"
##awk command I am using is as below
cat $diff | awk... (2 Replies)
Hi,
Please need to print the Rej variable outsite the awk script which is given below...please advised how to achieve it.
#!/bin/bash
echo "Enter DMU Pipe delimited File name for the Feed to be validated"
read DMU_File
echo "Enter Pre-DMU File name for the Feed"
read Predum_file
... (3 Replies)
Discussion started by: pelethangjam
3 Replies
LEARN ABOUT DEBIAN
devel::refcount
Devel::Refcount(3pm) User Contributed Perl Documentation Devel::Refcount(3pm)NAME
"Devel::Refcount" - obtain the REFCNT value of a referent
SYNOPSIS
use Devel::Refcount qw( refcount );
my $anon = [];
print "Anon ARRAY $anon has " . refcount($anon) . " reference
";
my $otherref = $anon;
print "Anon ARRAY $anon now has " . refcount($anon) . " references
";
DESCRIPTION
This module provides a single function which obtains the reference count of the object being pointed to by the passed reference value.
FUNCTIONS
$count = refcount($ref)
Returns the reference count of the object being pointed to by $ref.
COMPARISON WITH SvREFCNT
This function differs from "Devel::Peek::SvREFCNT" in that SvREFCNT() gives the reference count of the SV object itself that it is passed,
whereas refcount() gives the count of the object being pointed to. This allows it to give the count of any referent (i.e. ARRAY, HASH,
CODE, GLOB and Regexp types) as well.
Consider the following example program:
use Devel::Peek qw( SvREFCNT );
use Devel::Refcount qw( refcount );
sub printcount
{
my $name = shift;
printf "%30s has SvREFCNT=%d, refcount=%d
",
$name, SvREFCNT($_[0]), refcount($_[0]);
}
my $var = [];
printcount 'Initially, $var', $var;
my $othervar = $var;
printcount 'Before CODE ref, $var', $var;
printcount '$othervar', $othervar;
my $code = sub { undef $var };
printcount 'After CODE ref, $var', $var;
printcount '$othervar', $othervar;
This produces the output
Initially, $var has SvREFCNT=1, refcount=1
Before CODE ref, $var has SvREFCNT=1, refcount=2
$othervar has SvREFCNT=1, refcount=2
After CODE ref, $var has SvREFCNT=2, refcount=2
$othervar has SvREFCNT=1, refcount=2
Here, we see that SvREFCNT() counts the number of references to the SV object passed in as the scalar value - the $var or $othervar
respectively, whereas refcount() counts the number of reference values that point to the referent object - the anonymous ARRAY in this
case.
Before the CODE reference is constructed, both $var and $othervar have SvREFCNT() of 1, as they exist only in the current lexical pad. The
anonymous ARRAY has a refcount() of 2, because both $var and $othervar store a reference to it.
After the CODE reference is constructed, the $var variable now has an SvREFCNT() of 2, because it also appears in the lexical pad for the
new anonymous CODE block.
PURE-PERL FALLBACK
An XS implementation of this function is provided, and is used by default. If the XS library cannot be loaded, a fallback implementation in
pure perl using the "B" module is used instead. This will behave identically, but is much slower.
Rate pp xs
pp 225985/s -- -66%
xs 669570/s 196% --
SEE ALSO
o Test::Refcount - assert reference counts on objects
AUTHOR
Paul Evans <leonerd@leonerd.org.uk>
perl v5.14.2 2011-11-15 Devel::Refcount(3pm)