Thanks to everyone. For workaround I am using the same script which you have mentioned. But as i have mentioned I am converting .csv to text and using # as a field seperator. Below code is working fine. I need to reduce time in conversion etc.. I will try your code and will get back to you.
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Text file content...
I am running script like ---------- Post updated at 04:45 PM ---------- Previous update was at 04:40 PM ----------
Yes I know reading from file and write into file but not so much experience in that I am new to this perl. Thanks for your guidance.
Quote:
Originally Posted by dahlia84
To achive this, you need to know
1. How to read from a file using perl (search google for read a file in perl)
2. How to tell if a file exists in Perl (Check perl.about.com/od/filesystem/qt/perl_file_exist.htm)
For writing into logs, you can use something like this
In case your are stuck anywhere, post back with your code, people here are very helpful. They definitely will guide you!
Last edited by Franklin52; 10-28-2010 at 08:14 AM..
Reason: Please use code tags
HI
I need to read each line (test.txt) and store it in a array (@test)
How to do it in perl.
Suppose i have a file test.txt. I have to read each line of the test.txt file and store it in a array @test. How to do it in perl.
Regards
Harikrishna (3 Replies)
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TARGET DRIVE IO1 IO2 IO3 IO4 IO5
------------ --------- --------- --------- --------- ---------
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