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Top Forums Shell Programming and Scripting How to check if a partition is mounted or not with bash? Post 302466061 by bakunin on Monday 25th of October 2010 09:42:28 AM
Old 10-25-2010
Quote:
Originally Posted by cola
How to check if a partition is mounted or not with bash?
And when is $? variable one?
Please give example.
1. You can't "mount" a partition, only a "filesystem". This differentiation might seem picky, but in fact it is an important one.

2. You can't check it's mounting status with a shell, because a shell is a means to execute programs. You can use such a program - "mount", "df", probably some more - to find out if a filesystem is mounted, but that would be irregardless of the shell used.

3. "$?" is a variable set by an exiting program and contains the error code (or "error level"). If you want to know what an error level of 1 means for a certain program have a look in that programs man page.

4. You might want to read some introductory books about the Unix OS to get some basics. It won't do you any good in the long run, if you ask questions which show a clear lack of understanding of the underlying concepts. You might not understand the answer given and gain nothing from it - even if the answer is correct.

I hope this helps.

bakunin
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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