Substring using cut/awk/sed Post: 302464388

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Top Forums Shell Programming and Scripting Substring using cut/awk/sed Post 302464388 by ctsgnb on Wednesday 20th of October 2010 04:09:07 AM

10-20-2010

Registered User

sed will try to match the biggest pattern possible

Code:

# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\([0-9][0-9]\)/\1,\2,&/p'
MPMTR20,00,20100706043000.txt
# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\([0-9][0-9]\)/\1,\2,&/gp'
MPMTR20,00,20100706043000.txt
# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\([0-9][0-9]\)/\1,\2,&/1p'
MPMTR20,00,20100706043000.txt
#

and the & will be what is matched between the / / but it looks like a right expansion is performed since the .txt still remains

Note : The following will match nothing whereas we could have thought of a reverse search for the pattern like :
20100706043000
2010070604300
201007060430
20100706043
2010070604
...
see :

Code:

# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\([0-9][0-9]\)/\1,\2,&/2p'
# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\([0-9][0-9]\)/\1,\2,&/3p'
#

Note : that the \1 and \2 have their left and right expansion automatically performed even if not explicitly specified in the $ ...$ matching : look

Code:

# echo MPMTR20100706043000.txt|sed -n -e 's/\([0-9][0-9]\).*\(3[0-9][0-9]\)/\1,\2,&/p'
MPMTR20,300,20100706043000.txt

Last edited by ctsgnb; 10-20-2010 at 05:45 AM..

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