Hi
I want to convert MAY 05 2005 01:15:00PM date format to 2005/05/05 01:15:00PM .
CAn somebody suggest me a code ,I am new to unix shell programming.
Thanks
Arif (21 Replies)
Hi,
I have the string YYYYMMDDHHMMSS like 20090801204150 and I need to convert it using the unix command date in the format:
date "Saturday, 1 August 2009 20:40:59"
All in one single Unix line if this is possible. What's the correct syntax?
Steve Hagi (6 Replies)
Hi,
Iam trying to convert date and time to milliseconds which iam using in a script on Sun Solaris.
I have searched the posts on the forum but i could not get any solution.
The format iam using in script is:
date -u "Thu Dec 24 00:01:00 EST 2009"
But i get a bad command error.
... (6 Replies)
Hi,
I would like to convert the output from awk function to date and print on the screen.
Example : echo "Start Date: May 24 2010" | gawk -F": " '{print $2}'
Output : May 04 2010
I want this to be converted to 2010/05/24
Can i use date function here and how?
Thanks,
Deepika (2 Replies)
Hi all,
I require to convert julian date to normal calander date in unix
for eg julian date=122
now i want corresponding calander date
----------------------------------------
gr8 if give very small command/script
and please explain the steps as well(imp)
Thanks
... (3 Replies)
Hi all;
I am running a script:/var/tmp/gcsw -ne | grep "State:2" | wc
that gives me output like:80 480 6529
but i need this output as:2013-01-18 13:00 -> 80 480 6529 (1 Reply)
SOLARIS 9 Zone :
date command in crontab shows delayed(One Hour) output
Hi folks,
the date command shows the correct date and time, How ever, if the date command executed through crontab in any form of scrip the output shows as one hour delayed, similar to date -u..
Can some one help in... (12 Replies)
Hi ,
we have a string with yyyymmdd format .
how to know which date it is ?
example:20120712-->sunday
20150228-->saturday
20140431-->invalid
please suggest commands which work on below
os : SunOS 5.10
shell: bash shell
Thanks,
Srinath. (10 Replies)
Discussion started by: srinadhreddy27
10 Replies
LEARN ABOUT CENTOS
dm_date
DM_DATE(1) User Contributed Perl Documentation DM_DATE(1)NAME
dm_date - print out the system date and time
SYNOPSIS
This performs the same operation as the unix 'date' command, but using the Date::Manip module.
dm_date [OPTION]... [+FORMAT]
DESCRIPTION
This displays information about the current system time, or some other time. Options are:
-h, --help
Print online help.
-d STRING, --date=STRING
Display time described by STRING. STRING can be any string which can be parsed by Date::Manip. Please refer to the Date::Manip::Date
documentation for details.
-f DATEFILE, --file=DATEFILE
This reads each line in DATEFILE, and extracts a date from it and prints out the information.
Blank lines and lines starting with a pound (#) are ignored. Lines not containing a valid date are also ignored.
-r FILE, --reference=FILE
Displays the last modification time of FILE.
-R, --rfc-2822
Displayc the date and time in RFC 2822 format.
Example: Mon, 07 Aug 2006 12:34:56 -0600
-u, --utc, --universal
Converts the date to UT (GMT) and prints out the information.
Only one of -d, -f, or -r should be included. If more than one is included, the first one from the list (-d, -f, -r) is used and any other
is ignored.
The format string starts with a plus (+) and contains any of the format directives described in Date::Manip::Date.
KNOWN BUGS
None known.
BUGS AND QUESTIONS
Please refer to the Date::Manip::Problems documentation for information on submitting bug reports or questions to the author.
SEE ALSO
Date::Manip::Date
LICENSE
This script is free software; you can redistribute it and/or modify it under the same terms as Perl itself.
AUTHOR
Sullivan Beck (sbeck@cpan.org)
perl v5.16.3 2014-06-09 DM_DATE(1)