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Full Discussion: Display output bash program
Top Forums Shell Programming and Scripting Display output bash program Post 302463705 by pravin27 on Monday 18th of October 2010 08:30:57 AM
Old 10-18-2010
Try this,

Code:
#!/bin/bash

BESTANDEN=$* # Plaatst bestanden in de variabele BESTANDEN
TMPFILE=xmlprog.sh.$$.$RANDOM # basisnaam voor tijdelijke bestanden

# controller of het programma correct is aangeroepen
if [ -z "$BESTANDEN" ]
then
    echo "FOUT: Er zijn geen bestanden opgegeven!" >&2
    exit
fi

for i in $BESTANDEN 
do
    # Delete XML TAGS
echo $(sed -e 's/></>\n</g' $i | sed 's/<\/.*>//g' | sed 's/.*\(<.*>\).*/\1/' | sed '/^$/d' | wc -l) " opening tags in file " $i
done

 

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TMPFILE(3)								 1								TMPFILE(3)

tmpfile - Creates a temporary file

SYNOPSIS
resource tmpfile (void ) DESCRIPTION
Creates a temporary file with a unique name in read-write (w+) mode and returns a file handle . The file is automatically removed when closed (for example, by calling fclose(3), or when there are no remaining references to the file handle returned by tmpfile(3)), or when the script ends. For details, consult your system documentation on the tmpfile(3) function, as well as the stdio.h header file. RETURN VALUES
Returns a file handle, similar to the one returned by fopen(3), for the new file or FALSE on failure. EXAMPLES
Example #1 tmpfile(3) example <?php $temp = tmpfile(); fwrite($temp, "writing to tempfile"); fseek($temp, 0); echo fread($temp, 1024); fclose($temp); // this removes the file ?> The above example will output: writing to tempfile SEE ALSO
tempnam(3), sys_get_temp_dir(3). PHP Documentation Group TMPFILE(3)
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