I want to search for a word from the root directory using grep command.
I am searching for a word called batch in cd /vol directory.The vol directory has so many sub-directories and I want to see all the files having the name as batch.
This what I tried ..
/vol/ % grep -i *batch*
But it is... (4 Replies)
Hello Everybody,
I have files; yyyymmdd.log which the data look like this;
"Txid=9426043&MsgTxt=Thankyou&UserId=john&Password=jh2501"
"Txid=9426150&MsgTxt=Thankyou&UserId=john&Password=jh2501"
.
.
.
"Txid=9426200&MsgTxt=Thankyou&UserId=john&Password=jh2501"
Question 1:
How to... (3 Replies)
hello people,
All my servers have 4 mounts with this norme. For example, if my hostname is siroe.
df -h | grep `hostname`
/dev/dsk/c1t3d0s6 404G 399G 800M 100% /siroe3
/dev/dsk/c1t2d0s6 404G 399G 800M 100% /siroe2
/dev/md/dsk/d6 20G 812M 19G ... (3 Replies)
Instead of using the following command
#dmesg | grep -v sendmail | grep -v xntpd
How can I use just one grep -v and give both arguments.
Please suggest
thanks (4 Replies)
i have files with "DOMAINSOLVER ACMS" with any number of spaces in between the two words on its own line and i can find it with the following:
grep -c "DOMAINSOLVER* ACMS" $FILENAMEbut i need to exclude any lines matching: "$DOMAINSOLVER". i've tried a variety of quoting and escaping with no luck.... (4 Replies)
is there anyway i can ask grep to only get the first line?
as in the top command line
line 1 <-- just grep this line
line 2
line 3
---------- Post updated at 04:24 PM ---------- Previous update was at 04:19 PM ----------
nvm.. found out that i can do it with
|head (12 Replies)
Hello all,
I'm trying to grep the string "scott" from all files whose names are like srvr*.log and that were created "Nov 15"...I'm trying the following command but throws an error message...seems like the syntax is incorrect..
grep scott < ls -l srvr*.log|grep "Nov 15"
Thanks for your... (9 Replies)
My grep returns a row of data like this:
75=20130130;60=074338;61=985;511=55473883;452=115439;62=196;267=1;
Is there a way for the grep to only return 60="something" and 511="something" ?
Thanks in advance. (10 Replies)
Discussion started by: Carl2013
10 Replies
LEARN ABOUT REDHAT
zipgrep
ZIPGREP(1L)ZIPGREP(1L)NAME
zipgrep - search files in a ZIP archive for lines matching a pattern
SYNOPSIS
zipgrep [egrep_options] pattern file[.zip] [file(s) ...] [-x xfile(s) ...]
DESCRIPTION
zipgrep will search files within a ZIP archive for lines matching the given string or pattern. zipgrep is a shell script and requires
egrep(1) and unzip(1L) to function. Its output is identical to that of egrep(1).
ARGUMENTS
pattern
The pattern to be located within a ZIP archive. Any string or regular expression accepted by egrep(1) may be used. file[.zip] Path
of the ZIP archive. (Wildcard expressions for the ZIP archive name are not supported.) If the literal filename is not found, the
suffix .zip is appended. Note that self-extracting ZIP files are supported, as with any other ZIP archive; just specify the .exe
suffix (if any) explicitly.
[file(s)]
An optional list of archive members to be processed, separated by spaces. If no member files are specified, all members of the ZIP
archive are searched. Regular expressions (wildcards) may be used to match multiple members:
* matches a sequence of 0 or more characters
? matches exactly 1 character
[...] matches any single character found inside the brackets; ranges are specified by a beginning character, a hyphen, and an end-
ing character. If an exclamation point or a caret (`!' or `^') follows the left bracket, then the range of characters within
the brackets is complemented (that is, anything except the characters inside the brackets is considered a match).
(Be sure to quote any character that might otherwise be interpreted or modified by the operating system.)
[-x xfile(s)]
An optional list of archive members to be excluded from processing. Since wildcard characters match directory separators (`/'),
this option may be used to exclude any files that are in subdirectories. For example, ``zipgrep grumpy foo *.[ch] -x */*'' would
search for the string ``grumpy'' in all C source files in the main directory of the ``foo'' archive, but none in any subdirectories.
Without the -x option, all C source files in all directories within the zipfile would be searched.
OPTIONS
All options prior to the ZIP archive filename are passed to egrep(1).
SEE ALSO egrep(1), unzip(1L), zip(1L), funzip(1L), zipcloak(1L), zipinfo(1L), zipnote(1L), zipsplit(1L)URL
The Info-ZIP home page is currently at
http://www.info-zip.org/pub/infozip/
or
ftp://ftp.info-zip.org/pub/infozip/ .
AUTHORS
zipgrep was written by Jean-loup Gailly.
Info-ZIP 17 February 2002 ZIPGREP(1L)