or I don't know how to make it work ...
Hello
im trying to build regexp that will match me single string or function call inside of brackets
for example I have :
<% myFunction("blah",foo) %>
or
<% myVar %>
and not match :
<% if(myFunction("blah",foo)==1) %>
or
<% while(myvar < 3){... (2 Replies)
Hi everybody
for file in *
#Bash performs filename expansion
#+ on expressions that globbing recognizes.
do
output="`grep -n "$1" "$file"`"
echo "$file: `expr "$output" : '\(^.*$\)'`"
done
In the above bash script segment, I try to print just the first line of string named... (3 Replies)
Hi. Here's a tricky one (at least to me):
I have a file named theFile.txt (UTF-8) that contains the following:
a
b
cWhen I execute
perl -pe 's|a.*c|d|sg' theFile.txtin bash 3.2 on MAC OS X 10.6, I get no match, i.e. the result is
a
b
cagain. Any clues why? (2 Replies)
Hi,
I searched in the forums, but I didn't find a good solution. My problem is:
I have a string like "TEST.ABC201005.MONTHLY.D101010203".
I just want to have the string until the D100430, so that the string should look like: "TEST.ABC201005.MONTHLY.D"
The last characters after the D can be... (8 Replies)
Hello everyone,
I'm new in tcl scripting.
I'm currently studying a tcl script and came across this line:
regexp {(\d+)(\S?)} $opts match opt swi
According to my understanding, this line means to search in the opts variable for one or more digit, followed by a non-whitespace character... (2 Replies)
I'm probably just not thinking of the correct term to search for :-) But I want to match a pattern that might be 'ABC' or '1ABC' there might be three characters, or there might be four, but if there are four, the first has to be 1 (1 Reply)
Hi All,
I have a file fo around 15k bytes which i need to insert a string " + "at every 250 bytes.
I found some ideas here using perl to split into lines and tried to addapt it but the results where not satisfactory
for instance i tried to change
#!/usr/bin/perl
$teststring =... (9 Replies)
Greetings Experts,
I am in AIX; I have a file generated through awk after processing the input files. Now I need to replace or remove the new-line characters on all lines that doesn't have a ; which is the last character on the line. I tried to use sed 's/\n/ /g' After checking through the... (6 Replies)
For a given string that may contain any ASCII chars, i.e. that matches .*,
find and print only the chars that are in a given subset.
The string could also have numbers, uppercase, special chars such as ~!@#$%^&*(){}\", whatever a user could type in
without going esoteric
For simplicity take... (1 Reply)
Hi All,
I need to print the characters in the previous line just before the regular expression match
Please have a look at the input file as attached
I need to match the regular expression ^ with the character of the previous like and also the pin numbers
and the output file should be like... (6 Replies)
Discussion started by: kshitij
6 Replies
LEARN ABOUT V7
zgrep
ZGREP(1) General Commands Manual ZGREP(1)NAME
zgrep - search possibly compressed files for a regular expression
SYNOPSIS
zgrep [ grep_options ] [ -e ] pattern filename...
DESCRIPTION
Zgrep invokes grep on compressed or gzipped files. These grep options will cause zgrep to terminate with an error code:
(-[drRzZ]|--di*|--exc*|--inc*|--rec*|--nu*). All other options specified are passed directly to grep. If no file is specified, then the
standard input is decompressed if necessary and fed to grep. Otherwise the given files are uncompressed if necessary and fed to grep.
If the GREP environment variable is set, zgrep uses it as the grep program to be invoked.
EXIT CODE
2 - An option that is not supported was specified.
AUTHOR
Charles Levert (charles@comm.polymtl.ca)
SEE ALSO grep(1), gzexe(1), gzip(1), zdiff(1), zforce(1), zmore(1), znew(1)ZGREP(1)