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Full Discussion: Help with PERL loop
Top Forums Shell Programming and Scripting Help with PERL loop Post 302461356 by zero3ree on Sunday 10th of October 2010 06:31:40 PM
Old 10-10-2010
Help with PERL loop

I wrote a script to list all lines in a file with Perl. I am having trouble with the looping part of it. My script is supposed to look at the file and as long as the file is larger than the current line it prints a new line.

I am getting an error that won't stop on the while line of my code I believe.
Here is the code:

perl code:
  1. #!/usr/bin/perl -w
  2. unless(scalar(@ARGV)==1){
  3.    print "error: incorrect number of arguments",
  4.    "\n",
  5.    "usage: linenum.pl [filename]",
  6.    "\n";
  7.       exit 1;
  8. }
  9.  
  10. # Open function used with  filehandle and input file.
  11. open(MY_FILE, "$ARGV[0]") or die
  12.    "error: argument must be a file\n",
  13.    "usage: linenum.pl [filename]\n$!\n";
  14.  
  15. # Check if file is a directory
  16. if (!-f "$ARGV[0]"){
  17.    print "error: argument must be a file",
  18.    "\n",
  19.    "usage: linenum.pl [filename]\n";
  20.    exit 1;
  21. }
  22.  
  23. $COUNTER=1;  # Used for printing line numbers
  24.  
  25. # Loop and write lines from
  26. while($LINE <= <MY_FILE>){
  27.    # Adds leading zeros for numbers 1 digit long
  28.    if ($COUNTER<10){
  29.       print "000";
  30.    }
  31.    # Adds leading zeros for numbers 2 digits long
  32.    if (($COUNTER>9) && ($COUNTER<100)){
  33.       print "00";
  34.    }
  35.    # Adds leading zeros for numbers 3 digits long
  36.    if (($COUNTER>99) && ($COUNTER<1000)){
  37.    print "0";
  38.    }
  39.    # Prints line number and line
  40.    print "$COUNTER: $LINE";
  41.    $COUNTER+=1;
  42. }
  43.  
  44. exit 0;
 

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