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Top Forums Shell Programming and Scripting Custom directory path variable Post 302461043 by Chronomaly on Friday 8th of October 2010 09:55:42 AM
Old 10-08-2010
Quote:
Originally Posted by vbe
From what I understand now, is :
Your script does a cd
No, that's exactly what it can't do since the directory specified might not exist.

Quote:
the 2 first examples will work not the next ones, why?
None of the examples work atm since I'm not sure how to do this. I probably could make them all work by making loads of if arguments and substr's. That feels more like a workaround to me though, and I'm looking for a direct way to do this.

Quote:
(clue: Commonly in unix, not giving the path is uderstood as *relative" to current, as you can see why your two last examples will not work.
Actually the first example was using a relative path as well.

Quote:
You would now have to write a few tests in your script to see if argument could be a directory in a tree using the command find and hope it is unique if not... I let you choose the way you want to end...
Like I said, the directory might not exist and the point is to grab directory names from the syntax argument so I wouldn't know what to search for.
 

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SHELL-QUOTE(1)						User Contributed Perl Documentation					    SHELL-QUOTE(1)

NAME
shell-quote - quote arguments for safe use, unmodified in a shell command SYNOPSIS
shell-quote [switch]... arg... DESCRIPTION
shell-quote lets you pass arbitrary strings through the shell so that they won't be changed by the shell. This lets you process commands or files with embedded white space or shell globbing characters safely. Here are a few examples. EXAMPLES
ssh preserving args When running a remote command with ssh, ssh doesn't preserve the separate arguments it receives. It just joins them with spaces and passes them to "$SHELL -c". This doesn't work as intended: ssh host touch 'hi there' # fails It creates 2 files, hi and there. Instead, do this: cmd=`shell-quote touch 'hi there'` ssh host "$cmd" This gives you just 1 file, hi there. process find output It's not ordinarily possible to process an arbitrary list of files output by find with a shell script. Anything you put in $IFS to split up the output could legitimately be in a file's name. Here's how you can do it using shell-quote: eval set -- `find -type f -print0 | xargs -0 shell-quote --` debug shell scripts shell-quote is better than echo for debugging shell scripts. debug() { [ -z "$debug" ] || shell-quote "debug:" "$@" } With echo you can't tell the difference between "debug 'foo bar'" and "debug foo bar", but with shell-quote you can. save a command for later shell-quote can be used to build up a shell command to run later. Say you want the user to be able to give you switches for a command you're going to run. If you don't want the switches to be re-evaluated by the shell (which is usually a good idea, else there are things the user can't pass through), you can do something like this: user_switches= while [ $# != 0 ] do case x$1 in x--pass-through) [ $# -gt 1 ] || die "need an argument for $1" user_switches="$user_switches "`shell-quote -- "$2"` shift;; # process other switches esac shift done # later eval "shell-quote some-command $user_switches my args" OPTIONS
--debug Turn debugging on. --help Show the usage message and die. --version Show the version number and exit. AVAILABILITY
The code is licensed under the GNU GPL. Check http://www.argon.org/~roderick/ or CPAN for updated versions. AUTHOR
Roderick Schertler <roderick@argon.org> perl v5.16.3 2010-06-11 SHELL-QUOTE(1)
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