Command ls -l *cpp lists all cpp program files in a directory. It shows the size of each file. Using a calculator to work out the total size of the cpp files would be very tedious.
Is there a way to get the total size from the command line?
Can some one help ......
I want to list files with no extension in directory.
I have tried the following
ls * That listed all files
ls *.* That listed files with extension
ls That listed all files
Thanks (5 Replies)
Hi,
*.xml files stored on date wise folders. I need to extract *.xml files from all the folders. File size is lessthan or equal to 2K. Please let me know command or some shell program to due this job on linux m/c
This is urgent,
Thanks in advance
- Bache Gowda (3 Replies)
Hi,
I need to find files list which are more than 300 MB size? My script It should search all inner directories too.
How can I proceed? Any idea? (2 Replies)
Hi guys,
I need to do 100 files comparison after I sorted the files. There are no specific key for sorting so i plan to arrange the files based on the file size. The command that i used to sort the files by size is as per below:-
ls -l | sort +4rn | awk '{print $5, $9}'
The problem that i... (3 Replies)
Hello,
I've downloaded a huge amont of files
I've got a list of files from a remote server.
-rw-r--r-- 1 str661 strem 453465260 Dec 16 15:54 SATRYS2V1_20021218_temp_bias.nc
-rw-r--r-- 1 str661 strem 17669468 Dec 16 18:01 SATRYS2V1_20021225_hdyn_bias.nc
-rw-r--r-- 1... (9 Replies)
Hi,
I know that to list files with no extension, we can use..
ls -1 | grep -v "\."
And to list .prog files, we can use..
ls -1 *.prog
or
ls -1 | grep '.prog$' (4 Replies)
I need to write a script to :
list files with *.i extension in a directory and all its subdirectories + 30days old, save it in a file and then remove (2 Replies)
Hello,
I have a huge directory (with millions of files) and need to find out duplicates based on BOTH file name and File size.
I know fdupes but it calculates MD5 which is very time-consuming and especially it takes forever as I have millions of files.
Can anyone please suggest a script or... (7 Replies)
Hi All,
I want to fetch the files based on .done file and display the .csv files and Wil take .csv files for processing.
1.I need to display the .done files from the directory.
2.next i need to search for the .Csv files based on .done file.then move .csv files for the one directory
... (2 Replies)
Discussion started by: girija.g6
2 Replies
LEARN ABOUT REDHAT
gendiff
GENDIFF(1) General Commands Manual GENDIFF(1)NAME
gendiff - utility to aid in error-free diff file generation
SYNOPSIS
gendiff <directory> <diff-extension>
DESCRIPTION
gendiff is a rather simple script which aids in generating a diff file from a single directory. It takes a directory name and a "diff-
extension" as its only arguments. The diff extension should be a unique sequence of characters added to the end of all original, unmodi-
fied files. The output of the program is a diff file which may be applied with the patch program to recreate the changes.
The usual sequence of events for creating a diff is to create two identical directories, make changes in one directory, and then use the
diff utility to create a list of differences between the two. Using gendiff eliminates the need for the extra, original and unmodified
directory copy. Instead, only the individual files that are modified need to be saved.
Before editing a file, copy the file, appending the extension you have chosen to the filename. I.e. if you were going to edit somefile.cpp
and have chosen the extension "fix", copy it to somefile.cpp.fix before editing it. Then edit the first copy (somefile.cpp).
After editing all the files you need to edit in this fashion, enter the directory one level above where your source code resides, and then
type
$ gendiff somedirectory .fix > mydiff-fix.patch
You should redirect the output to a file (as illustrated) unless you want to see the results on stdout.
SEE ALSO diff(1), patch(1)AUTHOR
Marc Ewing <marc@redhat.com>
4th Berkeley Distribution Mon Jan 10 2000 GENDIFF(1)