cat ind_sls_extr_UX.out_sorted | while read each_rec
do
count=`echo "${each_rec}" | cut -c1-2`
if [ ${count} -eq 45 ]
then
final_amount=0
amount=`echo "${each_rec}" | cut -c280-287`
echo "${amount}"
final_amount=`expr ${amount} + ${amount}`
fi
done
The value amount is fetching a decimal value, but in final amount the value is not getting summed up :
Code:
00454.74
expr: An integer value was expected.
00454.74
expr: An integer value was expected.
00454.74
expr: An integer value was expected.
00454.74
expr: An integer value was expected.
00454.74
expr: An integer value was expected.
00454.74
expr: An integer value was expected.
How to resolve it.
Moderator's Comments:
Use code tags to display code, data, logs etc. please, ty.
Hi All,
Is there any command which can convert binary decimal coded values to ascii values...
i have bcd values like below
оооооооооооо0о-- -v -
Pls suggest a way to convert this.
Thanks,
Deepti.Gaur (3 Replies)
Hi guys I'm trying to print average of 2 columns.
awk '{print ($1+$2)/2}' file.txt
Its printing average but not giving decimal values
its giving 3.05521e+08 instead of 305521....
I tried %f to print float values but not quiet connected
Could you help plz:confused: (5 Replies)
Hi,
I have a small requirement where i need to sum up a column in a text file.
Input file
66ab 000000 534385 -00000106350.00
66cd 000000 534485 -00013364511.00
66ad 000000 534485 -00000426548.00
672a 000000 534485 000000650339.82... (5 Replies)
Hi All,
In my script I've written like this-
c=$( expr 100 / 3);echo $c
The output coming is 33. but I want to see 33.33, decimal values too. How to get that?
Thanks,
Naresh (3 Replies)
Hi Friends,
This is my last post for today.
My input file is
chr1 100 200
chr1 123 300
chr1 300 400
chr1 420 520
chr10 132344343 132348674
When I try using this command
awk '{v=($3+$2)/2; print $0"\t"v}' 1
This is my output
chr1 100 200 150
chr1 123 300 211.5 (2 Replies)
I have 2 files say tp1.txt and tp2.txt having following data
cat tp1.txt
abc,2.20,IN20
acb,3.15,DN10
bca,3,RD10
cat tp2.txt
alv,1.00,IN20
aaa,4.05,DD10
abb,5.50,RD12
i want to compare the values on 2nd field of both the file, if value of first tp1.txt is greater than value... (3 Replies)
Discussion started by: ranabhavish
3 Replies
8. Post Here to Contact Site Administrators and Moderators
HI Everyone,
I have below source file
AAA|NAME1|ADDRESS1|300.20
BBB|NAME2|ADDRESS2|400.31
CCC|NAME3|ADDRESS3|300.34
I have requirement where I need to sum up fourth field in above fixed width pipe delimited flat file. When I use below code, it gives me value 1001.00
But I am expecting... (1 Reply)
I used the below script to Sum up a field in a file based on some unique values. But the problem is when it is summing up the units, it is truncating to 2 decimals and not 6 decimals as in the input file (Input file has the units with up to 6 Decimals – Sample data below, when the units in the 2... (4 Replies)
Discussion started by: brlsubbu
4 Replies
LEARN ABOUT V7
expr
EXPR(1) General Commands Manual EXPR(1)NAME
expr - evaluate arguments as an expression
SYNOPSIS
expr arg ...
DESCRIPTION
The arguments are taken as an expression. After evaluation, the result is written on the standard output. Each token of the expression is
a separate argument.
The operators and keywords are listed below. The list is in order of increasing precedence, with equal precedence operators grouped.
expr | expr
yields the first expr if it is neither null nor `0', otherwise yields the second expr.
expr & expr
yields the first expr if neither expr is null or `0', otherwise yields `0'.
expr relop expr
where relop is one of < <= = != >= >, yields `1' if the indicated comparison is true, `0' if false. The comparison is numeric if
both expr are integers, otherwise lexicographic.
expr + expr
expr - expr
addition or subtraction of the arguments.
expr * expr
expr / expr
expr % expr
multiplication, division, or remainder of the arguments.
expr : expr
The matching operator compares the string first argument with the regular expression second argument; regular expression syntax is
the same as that of ed(1). The (...) pattern symbols can be used to select a portion of the first argument. Otherwise, the
matching operator yields the number of characters matched (`0' on failure).
( expr )
parentheses for grouping.
Examples:
To add 1 to the Shell variable a:
a=`expr $a + 1`
To find the filename part (least significant part) of the pathname stored in variable a, which may or may not contain `/':
expr $a : '.*/(.*)' '|' $a
Note the quoted Shell metacharacters.
SEE ALSO ed(1), sh(1), test(1)DIAGNOSTICS
Expr returns the following exit codes:
0 if the expression is neither null nor `0',
1 if the expression is null or `0',
2 for invalid expressions.
EXPR(1)
10-01-2010
