The following DIBOL program is a re hash of a program published in Computer World Newspaper in the early 1970's. The original was written in Fortran
It converts a date in the format yyyymmdd into the number days that have elapsed since Jan 1 1900.
It also converts a number representing the number of days since Jan 1 1900 to a date.
hii all.
I have to get the date of the 7th day past from the current date.
if i give the current date as sep 3 then i must get the date as 27th of august.
can we get the values from the "cal" command.
cal | awk '{print $2}' will this type of command work.
actually my need is
if today is... (17 Replies)
Hi,
Anybody knows how to get what date was 28 days ago of the current system date through UNIX script.
Ex : - If today is 28th Mar 2010 then I have to delete the files which arrived on 1st Mar 2010, (15 Replies)
Hi i am writing a cron job.
so for it i need the 60 days old date form current date in variable.
Like today date is 27 jan 2011 then output value will be stote in variable in formet Nov 27.
i am using EST date, and tried lot of solution and see lot of post but it did not helpful for me. so... (3 Replies)
I am trying to find out the number of days between the current date and user defined date.
I took reference from here for the date2jd() function.
Modified the function according to my requirement. But its not working properly.
Original code from here is working fine.
#!/bin/sh... (1 Reply)
Well guys,
I know the right syntax for displaying the current date is $(date). However, I am planning to send emails to some customers which displays their subscription date, and then the expiry. The expiry being 30 days from the current date.
What would the right syntax be? (6 Replies)
hi all..
i want 2 know how 2 find 7days past date from current date..
when i used set datetime = `date '+%m%d%y'` i got 060613..
i just want to know hw to get 053013..
i tried using date functions but couldnt get it :( i use c shell and there is no chance that i can change that ..... (3 Replies)
I have to display only those subscribers which are in "unconnected state" and the date is 90 days older than today's date.
Below command is used for this purpose:
cat vfsubscriber_20170817.csv | sed -e 's/^"//' -e '1d' | nawk -F '",' '{if ( (substr($11,2,4) == 2017) && ( substr($11,2,8) -lt... (1 Reply)
current date command runs well
awk -v t="$(date +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
subtract 30 days fails
awk -v t="$(date --date="-30days" +%Y-%m-%d)" -F "'" '$1 < t' myname.dat
awk command in hp unix subtract 30 days automatically from current date without date illegal option error... (20 Replies)
Discussion started by: kmarcus
20 Replies
LEARN ABOUT REDHAT
shadow
SHADOW(5) File Formats Manual SHADOW(5)NAME
shadow - encrypted password file
DESCRIPTION
shadow contains the encrypted password information for user's accounts and optional the password aging information. Included is
Login name
Encrypted password
Days since Jan 1, 1970 that password was last changed
Days before password may be changed
Days after which password must be changed
Days before password is to expire that user is warned
Days after password expires that account is disabled
Days since Jan 1, 1970 that account is disabled
A reserved field
The password field must be filled. The encryped password consists of 13 to 24 characters from the 64 character alphabet a thru z, A thru
Z, 0 thru 9, . and /. Refer to crypt(3) for details on how this string is interpreted.
The date of the last password change is given as the number of days since Jan 1, 1970. The password may not be changed again until the
proper number of days have passed, and must be changed after the maximum number of days. If the minimum number of days required is greater
than the maximum number of day allowed, this password may not be changed by the user.
An account is considered to be inactive and is disabled if the password is not changed within the specified number of days after the pass-
word expires. An account will also be disabled on the specified day regardless of other password expiration information.
This information supercedes any password or password age information present in /etc/passwd.
This file must not be readable by regular users if password security is to be maintained.
FILES
/etc/passwd - user account information
/etc/shadow - encrypted user passwords
SEE ALSO chage(1), login(1), passwd(1), su(1), passwd(5), pwconv(8), pwunconv(8), sulogin(8)AUTHOR
Julianne Frances Haugh (jockgrrl@ix.netcom.com)
SHADOW(5)